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3 years ago

Which of the following statements are evidence that gases do not always behave ideally? Check all that apply.?

Physics

2 answers:

yaroslaw [1]3 years ago

8 0

Your answer will be A

Hope this helps you out a little

Lelechka [254]3 years ago

8 0

You can choose :

A) CO2 gas becomes dry ice (solid CO2) at 1 atm and –78.5 °C.

B) When two gases mix, Dalton's law of partial pressure follows.

C) At 4 K and 1 atm, helium is a liquid.

<em>Because all of them is the right answer.</em>

<h2>Further explanation</h2>

Gas is a substance that is composed of atoms or molecules (commonly called particles) with relatively far distances. Between gas particles, there are weak bonds, so weak are these bonds that the physical properties of substances are almost [1] not affected by the type of substance. For example fluorine and helium. Chemically the two are very different, but their physical behavior is very similar. Various studies conducted in the 1600s found that the physical properties of all gases were determined by:

Pressure (P)
Volume (V)
Number of moles (n)
Temperature (T)

The relationship between these variables is called the gas laws, and the gas that follows these laws is called the ideal gas. There are various kinds of gas laws, but for this discussion, we will discuss the ideal gas law and partial pressures and Dalton's law.

The Ideal Gas Law

When Avogadro's law, Charles's law, and Boyle's law combine to produce a statement called the ideal gas, which states that the volume of a gas is influenced by the number of moles, pressure, and temperature. Ideal gas shows that there must be gas-gas that have non-ideal behavior. There is not a single gas that follows the equation perfectly under all conditions. All real gases are non-ideal and deviate from the behavior predicted by equations.

Partial Pressure and Dalton's Law.

The ideal gas law applies not only to pure gas but also to gas mixtures. Gas has a very unconcerned nature to neighboring molecules so that the presence or absence of other gases is unchanged. It can be said, the pressure caused by gas when occupying a container alone is as large as the pressure caused by the gas when occupying the gas together with other gases. The total pressure is the amount of pressure from all gases.

Learn more

Gas laws brainly.com/question/1324262, brainly.com/question/6534032

Details

Class: High School

Subject: Physics

Keyword: Gas laws.

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NASA is concerned about the ability of a future lunar outpost to store the supplies necessary to support the astronauts the supp

IRINA_888 [86]

Complete question :

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Answer:

601000 N

Explanation:

Given that :

Acceleration due to gravity at lunar outpost = 1.6m/s²

Supported Weight of supplies = 1 * 10^5 N

Acceleration due to gravity on the earth surface = 9.8m/s²

Maximum weight of supplies as measured on EARTH :

Ratio of earth gravity to lunar post gravity:

(Earth gravity / Lunar post gravity) ;

(9.8 / 1.63) = 6.01

Hence, maximum weight of supplies as measured on EARTH should be :

6.01 * (1 × 10^5)

6.01 × 10^5

= 601000 N

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3 years ago

I need help with this

fredd [130]

We have here what is known as parallel combination of resistors.

Using the relation:

$\frac{1}{ r_{eff} } = \frac{1}{ r_{1} } + \frac{1}{ r_{2} } + \frac{1}{ r_{3} }.. . + \frac{1}{ r_{n} } \\$
And then we can turn take the inverse to get the effective resistance.

Where r is the magnitude of the resistance offered by each resistor.

In this case we have,
(every term has an mho in the end)
$\frac{1}{10000} + \frac{1}{2000} + \frac{1}{1000} \\ \\ = \frac{1}{1000} ( \frac{1}{10} + \frac{1}{2} + \frac{1}{1} ) \\ \\ = \frac{1}{1000} ( \frac{31}{20}) \\ \\ = \frac{31}{20000}$

To ger effective resistance take the inverse:
we get,
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So the current flowing using ohm's law,

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will be, 0.0139 Amperes.

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3 years ago

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Mrrafil [7]

Answer:

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3 years ago

A circular bird feeder 19.0 cm in radius has rotational inertia 0.130 kg·m2. It's suspended by a thin wire and is spinning slowl

soldi70 [24.7K]

Answer:

N₂=20.05 rpm

Explanation:

Given that

R= 19 cm

I=0.13 kg.m²

N₁ = 24.2 rpm

$\omega_1=\dfrac{2\pi \times 24.2}{60}\ rda/s$

ω₁= 2.5 rad/s

m= 173 g = 0.173 kg

v=1.2 m

Initial angular momentum L₁

L₁ = Iω₁ - m v r ( negative sign because bird coming opposite to motion of the wire motion)

Final linear momentum L₂

L₂= I₂ ω₂

I₂ = I + m r²

The is no any external torque that is why angular momentum will be conserve

L₁ = L₂

Iω₁ - m v r = I₂ ω₂

Iω₁ - m v r = ( I + m r²) ω₂

Now by putting the all values

Iω₁ - m v r = ( I + m r²) ω₂

0.13 x 2.5 - 0.173 x 1.2 x 0.19 = ( 0.13 + 0.173 x 0.19²) ω₂

0.325 - 0.0394 = 0.136 ω₂

ω₂ = 2.1 rad/s

$\omega_2=\dfrac{2\pi \times N_2}{60}$

N₂=20.05 rpm

3 0

3 years ago

One of the fastest recorded pitches major-league baseball, thrown by nolan ryan in 1974, was clocked at 100.8 mi/hr. If a pitch

lawyer [7]

<u>Answer:</u>

The ball fall vertically 2.69 ft by the time it reached home plate 60.0 ft away.

<u>Explanation:</u>

Fastest recorded pitches major-league baseball, thrown by nolan ryan in 1974 = 100.8 mi/hr = 44.8 m/s

The horizontal distance to home plate = 60.0 ft = 18.288 m

We have the horizontal velocity = 44.8 m/s

So time taken = 18.288/44.8 = 0.408 seconds.

The distance traveled by baseball vertically is found out by equation $s=ut+\frac{1}{2} at^2$

Here u =0m/s, a = 9.81 $m/s^2$ and t = 0.408 s

Substituting

$S = 0*0.408+\frac{1}{2} *9.81*0.408^2 = 0.82 m\\ \\S = 0.82 m= 2.69 ft$

So vertical distance traveled = 0.82 m = 2.69 ft

7 0

3 years ago

Read 2 more answers