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MakcuM [25]
3 years ago
10

The skater is has a mass of 75 kg. Find the total Potential energy of the skater at the top of the ramp at 6 m.

Physics
1 answer:
olga_2 [115]3 years ago
5 0
Epot= mgh= 75*9,81*6= 4415 j
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One end of a 34-m unstretchable rope is tied to a tree; the other end is tied to a car stuck in the mud. The motorist pulls side
anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34  Solving for H:

H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

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3 years ago
A mass of gas under constant pressure occupies a volume of 0.5 m3 at a temperature of 20°C. Using the formula for cubic expansio
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No cubic expansion given
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Why do aeroplanes take longer to fly west than east?
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suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
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I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

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L1/15=(200*200)/(400*400)
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3 years ago
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Answer:A

Explanation:Find attached picture file for details

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