Correct temperature is 80°F
Answer:
T_f = 38.83°F
Explanation:
We are given;
Volume; V = 8 ft³
Initial Pressure; P_i = 100 lbf/in² = 100 × 12² lbf/ft²
Initial temperature; T_i = 80°F = 539.67 °R
Time for outlet flow; t_o = 90 s
Mass flow rate at outlet; m'_o = 0.03 lb/s
Final pressure; P_f = 30 lbf/in² = 30 × 12² lbf/ft²
Now, from ideal gas equation,
Pv = RT
Where v is initial specific volume
R is ideal gas constant = 53.33 ft.lbf/°R
Thus;
v = RT/P
v_i = 53.33 × 539.67/(100 × 12²)
v_i = 2 ft³/lb
Formula for initial mass is;
m_i = V/v_i
m_i = 8/2
m_i = 4 lb
Now change in mass is given as;
Δm = m'_o × t_o
Δm = 0.03 × 90
Δm = 2.7 lb
Now,
m_f = m_i - Δm
Thus; m_f = 4 - 2.7
m_f = 1.3 lb
Similarly in above;
v_f = V/m_f
v_f = 8/1.3
v_f = 6.154 ft³/lb
Again;
Pv = RT
Thus;
T_f = P_f•v_f/R
T_f = (30 × 12² × 6.154)/53.33
T_f = 498.5°R
Converting to °F gives;
T_f = 38.83°F
Answer:
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Explanation:
hope this helps
Answer:
<em>Hey mate, here's ur answer</em>
<em>-------------------------------------------------------------</em>
<u><em>Loudness</em></u><em> refers to how a sound seems to a listener, whether it's loud or soft. </em>
<em>___________________________</em>
<u><em>Intensity </em></u><em> is the sound power per unit area. It is independent of the sensitivity of the human ears.</em>
<em>___________________________</em>
<em>The loudness of a sound relates the intensity of any given sound to the intensity at the threshold of hearing. It is measured in decibels (dB).</em>
<em>___________________________</em>
<em>Hope this helps</em>
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Answer:
hopefully alex quackity hahhaa
Explanation:
i hope this was free points and not an actual thing
Time = distance divided by speed
4,900 divide 1.5 = 3266.67
