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Dafna11 [192]
3 years ago
5

How many moles of NaOH are in 27.8 mL of 0.168 M NaOH?

Chemistry
1 answer:
Alex17521 [72]3 years ago
8 0
Your answer would be 0.00285 moles.
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Four students all do the same experiment for the science fair. They test reaction times for pushing a button when a specific col
emmasim [6.3K]
Sorry, Cant really tell how to differentiate the students and trial times
3 0
3 years ago
Structure for reductive ozonolysis of 3,5-dimethyl-4-octene​
brilliants [131]

Answer:

Scheme is Attached.

When 3,5 dimethyl-4- octene is react with ozone two products are obtain.

2-Methyl butanal and 2 pentanon.

The complete reaction is given in attached file.

3 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
7 0
2 years ago
Which of the following is not a step in balancing redox reactions in acidic solution, using the half-reaction method?
schepotkina [342]
B <span>Divide the chemical equation into two half-reaction equations, identifying which half-reaction is oxidation and which is reduction 
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7 0
3 years ago
Read 2 more answers
If a dog has a mass of 16.1 kg, what is its mass in the following units? Use scientific notation in all of your answers.
nekit [7.7K]

Answer:

16.1\times 10^3\ \text{g}

16.1\times 10^{6}\ \text{mg}

16.1\times 10^{9}\ \mu\text{g}

Explanation:

Mass of dog = 16.1\ \text{kg}

1\ \text{kg}=10^{3}\ \text{g}

1\ \text{kg}=10^{6}\ \text{mg}

1\ \text{kg}=10^{9}\ \mu\text{g}

So,

16.1\ \text{kg}=16.1\times 10^3\ \text{g}

16.1\ \text{kg}=16.1\times 10^{6}\ \text{mg}

16.1\ \text{kg}=16.1\times 10^{9}\ \mu\text{g}

Mass of the dog in the other units is 16.1\times 10^3\ \text{g}, 16.1\times 10^{6}\ \text{mg} and 16.1\times 10^{9}\ \mu\text{g}.

3 0
3 years ago
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