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geniusboy [140]
3 years ago
7

If an airplane were traveling eastward with a thrust force 450 N and there was a tailwind of 200 N, what would the resulting net

force be on the airplane?
*20 points*
Physics
2 answers:
WARRIOR [948]3 years ago
7 0

Answer:

The resulting net force is 650N

Explanation:

The force caused by air resistance against the plane's motion is called the Drag force. It acts against the motion of the plane. However, tailwinds push the plane from its tail and they apply a force is the direction of the moving plane.

The resulting force is the sum of the two forces; 450N +200N = 650N

Marrrta [24]3 years ago
5 0

Answer:

The resultant force is 650N

Explanation:

the force caused by air resistance against the plain's motion is called the drag force. It acts against the plain's motion

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Also, \Delta E=\frac {h\times c}{\lambda}

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h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

So,  

\frac {h\times c}{\lambda}=2.179\times 10^{-18}(|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)\ J

\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

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\lambda=\frac {6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times (|\frac{1}{n_i^2} - \dfrac{1}{n_f^2}|)}\ m

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\lambda=\frac{6.626\times 10^{-34}\times 3\times 10^8}{{2.179\times 10^{-18}}\times |(\frac{1}{3^2} - \dfrac{1}{1^2})}|\ m

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\lambda=1.03\times 10^{-7}\ m

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