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3 years ago

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Show work for the following examples

1 answer:

emmainna [20.7K]3 years ago

7 0

1) (1.00mol H2O2)(34.02g/mol H2O2) = 34.02g H2O2

2) (1.00mol NaNO3)(84.99g/mol NaNO3) = 84.99g NaNO3

3) (8.00mol Ar)(6.02x10²³) = 4.82x10²⁴ atoms

4) (132g Kr) / (83.79g/mol Kr) = 1.58mol Kr

5) (96.4g Si)/(28.09 g/mol Si) = 3.43mol Si
(3.43mol Si)(6.02x10²³) = 2.07x10²⁴ atoms Si

6) You did this one correctly :)

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compound of aspartame is a dipeptide that is often used as a sugar substitute which functional groups are present

Scrat [10]

Answer:

Carboxyl, primary amine, amide, ester, and phenyl.

Explanation:

The functional groups present in the compound of aspartame are carboxyl, primary amine, amide, ester, and phenyl. Aspartame is an artificial non-saccharide sweetener which is 200 times sweeter than sucrose. This aspartame is commonly used as a sugar substitute in many foods and beverages. It has the trade names such as NutraSweet, Equal, and Canderel.

5 0

3 years ago

Solve the ideal gas law equation for pressure.

posledela

Answer:

$p=\frac{nRT}{V}$

Explanation:

The ideal gas law equation is an equation that relates some of the quantities that describe a gas: pressure, volume and temperature.

The equation is:

$pV=nRT$

where

p is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature of the gas (must be expressed in Kelvin)

Here we want to solve the equation isolating p, the pressure of the gas.

We can do that simply by dividing both terms by the volume, V. We find:

$p=\frac{nRT}{V}$

So, we see that:

- The pressure is directly proportional to the temperature of the gas

- The pressure is inversely proportional to the volume of the gas

6 0

3 years ago

When copper is changed to copper(II) nitrate by the nitric acid, it is an example of a(n) ______-_______ reaction. (two words, i

Nataly_w [17]

Answer:

oxidation- reduction

Explanation:

where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent

<h2>Oxidize: copper = Cu+2</h2>

5 0

3 years ago

Explain reaction of metals with the following with the help of chemical equations. i) with acids ii) with oxygen iii) with water

Amiraneli [1.4K]

i. When an acid reacts with metal, a salt and hydrogen are produced:

ii. When oxygen and metal react, metal oxide forms also known as rust

iii. metal and water produce hydrogen gas

6 0

3 years ago

There are some data that suggest that zinc lozenges can significantly shorten the duration of a cold. If the solubility of zinc

zhuklara [117]

Answer:

$K_{sp}$ of $Zn(CH_{3}COO)_{2}$ is 0.0513

Explanation:

Solubility equilibrium of $Zn(CH_{3}COO)_{2}$ :

$Zn(CH_{3}COO)_{2}\rightleftharpoons Zn^{2+}+2CH_{3}COO^{-}$

Solubility product of $Zn(CH_{3}COO)_{2}$ ( $K_{sp}$ ) is written as- $K_{sp}=[Zn^{2+}][CH_{3}COO^{-}]^{2}$

Where $[Zn^{2+}]$ and $[CH_{3}COO^{-}]$ represents equilibrium concentration (in molarity) of $Zn^{2+}$ and $CH_{3}COO^{-}$ respectively.

Molar mass of $Zn(CH_{3}COO)_{2}$ = 183.48 g/mol

So, solubility of $Zn(CH_{3}COO)_{2}$ = $\frac{43.0}{183.48}M$ = 0.234M

1 mol of $Zn(CH_{3}COO)_{2}$ gives 1 mol of $Zn^{2+}$ and 2 moles of $CH_{3}COO^{-}$ upon dissociation.

so, $[Zn^{2+}]$ = 0.234 M and $[CH_{3}COO^{-}]$ = $(2\times 0.234)M=0.468M$

so, $K_{sp}=(0.234)\times (0.468)^{2}=0.0513$

8 0

4 years ago