How many grams of acetylene react if 1.10 mol of CO2 are produced?
1 answer:
Combustion of <span>acetylene :
</span><span>molar ma</span>ss acetylene ( C₂H₂ ) = 26.0 g/mol and CO₂ = 44.0 g/mol
<span>
2 C₂H₂ + 5 O₂ ---> 4 CO₂ + 2 H₂O
</span>
2 moles C₂H₂ --------> 4 moles CO₂
? moles C₂H₂ --------> 1.10 moles CO₂
moles C₂H₂ = 1.10 * 2 / 4
moles C₂H₂ = 0.55 moles of C₂H₂
Mass acetylene:
m = n * mm
m = 0.55 * 26.0
m = 14.3 g
hope this helps!
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