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Lera25 [3.4K]
3 years ago
15

What type of bonding is shown in the diagram

Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

Covalent Bond

Explanation:

In the diagram Carbon and each of the 4 Hydrogens are sharing electrons. They are also both non metals. Both of these are characteristics of Covalent Bonds.

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a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
3 years ago
What volume is occupied by 35.2 g of carbon tetrachloride if its density is 1.60 g/ml?
ycow [4]

Density is mass divided by volume. Therefore, volume is mass divided by density.

V=\frac{m}{\rho}=\frac{35.2g}{1.60\frac{g}{ml}}=22.0\ ml

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3 years ago
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The answer is:

D. Samples of ocean water.

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The time necessary for the decay of one- half sample of a radioactive substance is a _____. mass defect daughter half life nucli
Mazyrski [523]

Answer: half life

Explanation: Radioactive decay follows first order kinetics and the time required for the decay of a radioactive material is calculated as follows:

t=\frac{2.303}{k}\hspace{1mm}log\frac{x}{a}

t= time required

k= disintegration constant

x= amount of substance left after time t

a= initial amount of substance

when one half of the sample is decayed, one half of the sample remains and t can be represented as t_{1/2}

at t= t_{1/2}, x=\frac{a}{2}

t_{1/2}=\frac{2.303}{k}\hspace{1mm}log\frac{a/2}{a}

t_{1/2}=\frac{0.693}{k}

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Xian drew a diagram to compare deletion mutations and substitution mutations. Which label belongs in the area marked "X"? may ch
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Answer: (B)

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