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almond37 [142]
4 years ago
10

Why are adaptations important to organisms?

Physics
1 answer:
Serga [27]4 years ago
5 0
Adaptations can help organisms reproduce and continue living in different conditions
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Help with 2 Physics questions, WILL CHOOSE BRAINLIEST
Tju [1.3M]

1) D

2) D.) Greater than \theta_c

Explanation:

1)

The phenomenon of total internal reflection occurs when a ray of light hitting the interface between two mediums is totally reflected back into the original medium, therefore no refraction into the second medium occurs.

This phenomenon occurs only if two conditions are satisfied:

  • The index of refraction of the first medium is larger than the index of refraction of the 2nd medium
  • The angle of incidence is greater than a certain angle called critical angle

In picture 1, we have 4 different diagrams. In the diagrams:

  • The red arrow represents the incident ray
  • The green arrow represents the refracted ray
  • The blue arrow represents the reflected ray

Total internal reflection occurs when there is no refraction, therefore when there is no green arrow: this occurs only in figure D, so this is the correct option. (in figure C, there is a refracted ray but it is parallel to the interface: this condition occurs when the angle of incidence is exactly equal to the critical angle, however in this problem, the angle of incidence is greater than the critical angle, so the correct option is D)

2)

As we stated in problem 1), total internal reflection occurs when the angle of incidence is equal or greater than the critical angle. Therefore in this case, the angle of incidence must be

D.) Greater than \theta_c

3 0
3 years ago
A flywheel in a motor is spinning at 530 rpm when a power failure suddenly occurs. The flywheel has mass 40.0kg and diameter 75.
aleksley [76]

Answer:

 w = 25.05 rad / s ,     α = 0.7807 rad / s² ,   θ = 1972.75

Explanation:

This is a kinematic rotation exercise, let's start by looking for the acceleration when the engine is off

            θ = w₀ t - ½ α t²

            α = (w₀t - θ) 2/t²

           

let's reduce the magnitudes to the SI system

 

w₀ = 530 rev / min (2pi rad / 1 rev) (1 min / 60 s) = 55.5 rad / s

θ = 250 rev (2pi rad / 1 rev) = 1570.8 rad

 

let's calculate the angular acceleration

           α = (55.5 39 - 1570.8) 2/39²

           α = 0.7807 rad / s²

having the acceleration we can calculate the final speed

           w = w₀ - ∝ t

           w = 55.5 - 0.7807 39

           w = 25.05 rad / s

the time to stop w = 0

           0 = wo - alpha t

           t = wo / alpha

           t = 55.5 / 0.7807

           t = 71.09 s

         

the angle traveled

       w² = w₀⁹ - 2 α θ

       w = 0

      θ = w₀² / 2α

let's calculate

      θ = 55.5 2 / (2 0.7807)

        θ = 1972.75

5 0
3 years ago
Stan walks 10km west to the grocery store. He shops then walks back 10 km east back to his house. What distance did he cover? Wh
Lesechka [4]
Stan’s displaceent is 0 km because he ends his walk where he started.
6 0
3 years ago
When energy is changed from one form to another, some of the energy is lost to the surroundings as waste thermal energy. The mor
Taya2010 [7]
The answer is B Solar cell just took the test
7 0
4 years ago
Read 2 more answers
If y=5sin (3x -40)<br>Calculate the frequency and period​
ioda

Answer:

0.477 Hz

2.09 s

Explanation:

y = A sin(ωx − φ)

A is the amplitude, ω is the angular frequency, and φ is the phase shift.

ω = 3 rad/s

f = ω / 2π ≈ 0.477 Hz

T = 1/f ≈ 2.09 s

8 0
3 years ago
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