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almond37 [142]
3 years ago
10

Why are adaptations important to organisms?

Physics
1 answer:
Serga [27]3 years ago
5 0
Adaptations can help organisms reproduce and continue living in different conditions
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a bullet of mass 4g when fired with a velocity of 50m/s can enter a wall upto a depth of 10cm how much will be the average resis
jok3333 [9.3K]
Mass, m = 4g = 0.004 kg
Velocity, =  50cm/s = 0.5m/s
Distance, 10cm = 0.1m
The wall would have to resist the energy acquired by the bullet.

Kenetic Energy of bullet = Resistance offered by the wall.

1/2 mv²                        =  Resistance Force * Distance

(1/2) * 0.04 * 0.5 * 0.5 =  F * 0.1

0.5 * 0.04 * 0.5 * 0.5 =  F * 0.1

0.5 * 0.04 * 0.5 * 0.5/0.1 = F

0.05 = F

Therefore, Resistance offered by the wall = 0.05 N
8 0
3 years ago
What happens to the size of an Object when it is heated ?​
Solnce55 [7]

Answer:

size get smaller maybe there is no object remaining

3 0
3 years ago
Read 2 more answers
the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67​
baherus [9]

Answer:

\theta_c = 36.78^o

Explanation:

The relationship between the refractive index and the critical angle is given as follows:

\eta = \frac{1}{Sin\ \theta_c} \\\\Sin\ \theta_c = \frac{1}{\eta}\\\\\theta_c = Sin^{-1}(\frac{1}{\eta} )

where,

η = refractive index = 1.67

θc = critical angle =?

Therefore,

\theta_c = Sin^{-1}(\frac{1}{1.67} )

\theta_c = 36.78^o

4 0
3 years ago
Two point charges each have a value of 3.0 c and are separated by a distance of 4.0 m. what is the electric field at a point mid
swat32
 <span>Place a test charge in the middle. It is 2cm away from each charge. 
The electric field E= F/Q where F is the force at the point and Q is the charge causing the force in this point. 
The test charge will have zero net force on it. The left 30uC charge will push it to the right and the right 30uC charge will push it to the left. The left and right force will equal each other and cancel each other out. 
THIS IS A TRICK QUESTION. 
THe electric field exactly midway between them = 0/Q = 0. 
But if the point moves even slightly you need the following formula 
F= (1/4Piε)(Q1Q2/D^2) 
Assume your test charge is positive and make sure you remember two positive charges repel, two unlike charges attract. Draw the forces on the test charge out as vectors and find the magnetude of the force, then divide by the total charge to to find the electric field strength:)</span>
4 0
3 years ago
As light shines from air to water, the index of refraction is 1.02 and the angle of incidence is 38.0 °. What is the light's an
muminat

Answer:

Light's angle of refraction = 37.1° (Approx.)

Explanation:

Given:

Index of refraction = 1.02

Base of refraction = 1

Angle of incidence = 38°

Find:

Light's angle of refraction

Computation:

Using Snell's law;

Sin[Angle of incidence] / Sin[Light's angle of refraction] = Index of refraction / Base of refraction

Sin38 / Light's angle of refraction = 1.02 / 1

Sin[Light's angle of refraction] = Sin 38 / 1.02

Sin[Light's angle of refraction] = [0.6156] / 1.02

Sin[Light's angle of refraction] = 0.6035

Light's angle of refraction = 37.1° (Approx.)

5 0
3 years ago
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