The equatorial radius of the earth is
r = 6378 km = 6378 x 10³ m
The earth makes 1 revolution in 24 hours.
The angular velocity is
ω = (2π rad)/(24*3600 s) = 7.2722 x 10⁻⁵ rad/s
The tangential velocity (linear velocity) at a point on the equator is
v = rω
= (6378 x 10³ m)*(7.2722 x 10⁻⁵ rad/s)
= 463.8 m/s
Answer: 463.8 m/s
Answer:
The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>
Explanation:
Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m
Speed of data travel = speed of light ≈ 3 x 10⁸m/s
As, v=d/t
t=d/v
t=1.28s
RTT = Double of single way time taken = 2x1.28
<em><u>RTT=2.56s</u></em>
Answer:
4 hydrogen atoms can form chemical bond with 1 carbon atom.
Explanation:
CH4. methane
An example of using muscular strength would be doing things like lifting weights and things like that.
Answer:
<h2>
280.86 m</h2>
Explanation:
Range is defined as the distance covered in the horizontal direction. In projectile, range is expressed as x = vt where;
x is the range
v is the velocity of the runner
t is the time taken
Before we can get the range though, we need to find the time taken t using the relationship S = ut + 1/2gt²
if u = 0
S = 1/2gt²
2S = gt²
t² = 2S/g
t = √2S/g
t = √2(141)/9.8
t = √282/9.8
t = 5.36secs
The range x = 52.4*5.36
x =280.86 m
Hence, the coyort lies approximately 280.86 m from the base of the cliff
