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sergij07 [2.7K]
3 years ago
12

A 9.0-v battery is connected to a bulb whose resistance is 2.5 ω . part a how many electrons leave the battery per minute?

Physics
1 answer:
REY [17]3 years ago
3 0

Solution:

According to the formula I=V/R

so 9.0v/2.5ohm=3.6A

since 3.6A=3.6c/s

therefore for per minute

  3.6*60=216c leaving the battery.

Now,

Each electron carries a charge of 1.6*10^(-19)c

so 216/ 1.6*10^(-19)=1.35*10^21c

1.35*10^21c this is the required electrons leaving the battre per minute.


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