What are the typical bond angles (in degrees) in molecules with 4 electron groups?
1 answer:
The typical bond angles (in degrees) in molecules with 4 electron groups will be <u>109.5 degrees</u>.
The angle that exists among two covalent bonds that come from the same atom is known as a bond angle.
When there have four bonds and no lone pairs, the tetrahedral geometry occurs. Given that many molecules would adopt this geometry, it represents one of the most significant and prevalent geometries. For example, assumes a tetrahedral geometry. Tetrahedral molecules have a bond angle of around 109.5°.
Therefore, The typical bond angles (in degrees) in molecules with 4 electron groups will be <u>109.5 degrees</u>.
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Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series
Explanation:
Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.
Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.
In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .
Thus for mass number : 235 = 207+4X
4X= 28
X = 7
Thus for atomic number : 92 = 82+2X-Y
2X- Y = 10
2(7) - Y= 10
14-10 = Y
Y= 4
Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series
According to the statement
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid
<h3>What is neutralization?</h3>A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.
<h3>According to the given information:</h3>The equation of the neutralization reaction between H2SO4 and CaCO3.
CaCO3 + H2SO4 → CaSO4 + H2CO3
H2CO3 dissociate to water and carbon dioxide.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
Now solving for the mass of CaCO3 needed to neutralize the acid.
mass of CaCO3 = 9460 Kg H2SO4 ×
= 21284.56606
mass of CaCO3 = 2.12 x 10^4 lbs
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.
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