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4 years ago

Evaluate u + xy, for u = 1, x = 3, and y = 6.

1 answer:

Nutka1998 [239]4 years ago

6 0

Answer: hi! so the first thing you want to do is plug in for your variables.

so when you do that you get:

1+3(6)

according to PEMDAS, multiplication comes first.

6*3=18

so you’re equation should now look like this;

1+18

and then add the numbers together.

your answer should be 19.

hope this helps!!

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When large amplitude sound vibrates the ear significantly, a _______ results.

sladkih [1.3K]

The answer is B. High Pitch Sound

4 0

4 years ago

Please help these with these two questions

Gennadij [26K]

<h2>If the distance between Earth and moon is increased , the gravitational force will decrease by a proportional amount .</h2><h2>The iron filings sprinkle around the magnet are arranged in regular pattern . The reason for this is that magnet can attract magnetic substances through various materials .</h2>

Explanation:

If the distance between Earth and moon is increased , the gravitational force will decrease by a proportional amount .

The iron filings sprinkle around the magnet are arranged in regular pattern . The reason for this is that magnet can attract magnetic substances through various materials .

8 0

3 years ago

Solve for velocity in A car has traveled 456 meters in 45 seconds while driving east on Broad Street. What is the velocity of th

OLEGan [10]

Answer:

10.13

Explanation:

take note that velocity is distance over time ( $v=\frac{d}{t}$ ) so you do 456(distance)÷45(time)= 10.13

3 0

4 years ago

A flat roof is very susceptible to wind damage during a thunderstorm and/or tornado. If a flat roof has an area of 500 m2 and wi

Evgesh-ka [11]

Answer: The magnitude of the force exerted on the roof is 490522.5 N.

Explanation:

The given data is as follows.

Below the roof, $v_{1}$ = 0 m/s

At top of the roof, $v_{2}$ = 39 m/s

We assume that $P_{1}$ is the pressure at lower surface of the roof and $P_{2}$ be the pressure at upper surface of the roof.

Now, according to Bernoulli's theorem,

$P_{1} + 0.5 \times \rho \times v^{2}_{1} = P_{2} \times 0.5 \rho \times v^{2}_{2}$

$P_{1} - P_{2} = 0.5 \times \rho \times (v^{2}_{2} - v^{2}_{1})$

= $0.5 \times 1.29 \times [(39)^{2} - (0)^{2}]$

= $0.645 \times 1521$

= 981.045 Pa

Formula for net upward force of air exerted on the roof is as follows.

F = $(P_{1} - P_{2})A$

= $981.045 \times 500$

= 490522.5 N

Therefore, we can conclude that the magnitude of the force exerted on the roof is 490522.5 N.

5 0

3 years ago

There is no sound in the vaccuum of space. Why? Select all that apply

miss Akunina [59]

#1 and #3 are correct.

#3 is slightly goofy.
The problem is not that there's no air to vibrate your eardrum.
The problem with no air is that there's nothing to ever bring the sound
to your head, even if you're only a foot away from the source. There
are just NO SOUND WAVES going on at all.

7 0

3 years ago