The magnetic field b(t) due to this current is
Suppose that the current in the solenoid is i(t). Within the solenoid, but far from its ends, what is the magnetic field B(t) due to this current?
The magnetic field is the area around a magnet where there is magnetic force. Moving electric charges can make magnetic fields. Then a solenoid is the long coil of wire wrapped in many turns. When a current passes through, it creates a nearly uniform magnetic field inside.
Solenoids can convert electric current to mechanical action, and so are very commonly used as switches
Even small solenoids can exert forces of a few newtons.
If we look through the solenoid far from ends, we can use Ampere's law to calculate the field strength. The magnetic field (deep) within the solenoid has a uniform value B, and outside the coils has value zero.
The magnetic field within a solenoid depends upon the current and density of turns. The magnetic field B(t) due to this current is . This is derived from Ampere's law used to calculate the strength of magnetic field.
Where is number of coils per meter and
is current through wire.
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Answer:
d) It will be cut to a fourth of the original force.
Explanation:
The magnitude of the electrostatic force between the charged objects is
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
In this problem, the initial distance is doubled, so
r' = 2r
Therefore, the new electrostatic force will be
So, the force will be cut to 1/4 of the original value.