An erect object is placed on the central axis of a thin lens, further from the lens than the magnitude of its focal length. The
1 answer:
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Answer:
The final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.
Explanation:
Taking north direction as positive y axis and east direction as positive x axis .
Given:
Mass of first car is,
Initial velocity of first car is,
Mass of second car is,
Initial velocity of second car is,
Let the combined final velocity after collision be 'v' m/s with as components of final velocity along east and north directions respectively.
Now, as the net external force is zero, momentum is conserved for the two car system along the east and north directions.
Conserving momentum along the east direction, we have:
Initial momentum = Final momentum
There is no component of initial velocity for first car in east direction, as it is moving in the north direction. So,
Now, conserving momentum along the north direction, we have:
Initial momentum = Final momentum
There is no component of initial velocity for second car in north direction, as it is moving in the east direction. So, .
The magnitude of final velocity is given as:
The direction is given as:
So, the final velocity has a magnitude of 25.44 m/s and is at 31.61° north of east.
Answer:
The time constant becomes twice.
Explanation:
= Time constant of the L-R circuit
= Inductance of the inductor
= Resistance of the resistor
Time constant of the L-R circuit is given as
= initial time constant of the L-R circuit =
= final time constant of the L-R circuit
= Initial inductance of the inductor =
= Initial inductance of the inductor =
For the same resistance, the time constant depend directly on the inductance, hence
119.7kPa
Explanation:
Given parameters:
Pressure of gas in balloon = 111kPa
Temperature of gas = 22°C
Final temperature = 45°C
Unknown:
Final pressure = ?
Solution:
Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.
At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.
P1 is the initial pressure
P2 is the final pressure
T1 is the initial temperature
T2 is the final temperature
convert from celcius to kelvin:
tK = 273 + tC
T1 = 273 + 22 = 295K
T2 = 273 + 45 = 318K
P2 = 119.7kPa
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