<h3><u>
We are given:</u></h3>
Coefficient of Kinetic Friction = 0.2
Mass of the crate = 1000 kg
Force applied = 2000 N
<h2 /><h2><u>
Net force Acting on the crate in the Horizontal Direction:</u></h2><h3>
<u>Normal Force applied on the Crate:</u></h3>
Normal force is the force applied on the object by the surface. It is equal and opposite to the force of gravity
So, we can say that Normal force = | Gravitational Force |
Normal Force = | mg |
Normal Force = 1000 * 9.8
Normal Force = 9800 N
<h3><u>
Finding the Frictional Force:</u></h3>
We know that:
coefficient of Kinetic friction = Friction force / Normal force
<em>replacing the known values</em>
0.2 = Friction force / 9800
Friction Force= 0.2 * 9800
Friction Force = 1960 N
<h3><u>
Net force acting on the Crate:</u></h3>
We know that a force of 2000 N is being applied on the crate in the Horizontal direction
Frictional force is always opposite to the horizontal force. So, we can say that:
Applied force - Friction Force = Net Force
<em>replacing the variables</em>
2000 - 1960 = Net force
Net Force = 40N
Therefore, a net force of 40N is being applied on the Crate
<h2>
</h2><h2><u>
Acceleration of the Crate:</u></h2>
From newton's second law of motion:
F = ma
<em>replacing the variables</em>
40 = 1000 * a
a = 40/1000
a = 0.04 m/s²
Hence, the crate will have an acceleration of 0.04 m/s²