The correct answer is option C. <span>All objects reflect some light. If the object is in front of a mirror, the mirror reflects the light back toward the object, and an image is formed by the reflected rays.</span>The mirror reflects light and does not absorb. Reflection can be specular or diffused.
Answer: Radio signals sent through space
Explanation:
>Radio signals are electromagnetic signals which can travel through space even in vacuum where no air is absent . Radio signals carry energy in the form of electromagnetic wave .
>Thunder heard from many miles away is due to propagation of sound wave in the air or atmosphere . The sound wave carries energy in the form of mechanical energy which can not propagate in vacuum and requires a medium .
>When nuclei of atoms split into parts they fly away from each other with some speed carrying kinetic energy which is a part of mechanical energy .
Thus mechanical energy is involved in all the given examples expect the case of radio signals sent through space.
Answer:
the velocity is 1.67 m/s
Explanation:
The computation of the velocity of the arrow/ice combination after the collison is shown below:
Here the law of conservation is applied
Here
Now
= 1.67 m/s
hence, the velocity is 1.67 m/s
Answer:
true 1
2 is false 2. 3 . 4. 5
Explanation:
For this exercise, let's calculate the different parameters and analyze the corresponding statements.
the resistance of each wire
R = ρ
wire B.
has a diameter of d₀
therefore its radius is r₀ = d₀ / 2
the area is A = pi r₀²
A = π d₀²/ 4
we subtitle
Ro = ρ
R_b = R₀
wire A
the diameter is d = 2d₀
therefore the radius is r = d/2
r = d₀
resistance is
R_a = ρ
R_a = 4 R₀
when examining the answers
1 is true
4 is false
Now let's calculate the power
P = V I
V = I R
P = V² / R
as they indicate that the cables are connected in parallel, the voltage in them is the same, therefore the potency depends on the resistance
wire B
P = V² / R_b
P_b = V² / R₀
wire A
P_a = v² / R_a
P_a = V² / 4R₀
P_a = ¼ P_b
2 is false
in a parallel circuit the waves are the same therefore
3 False
ohm's law is
V = I r
I = V / R
wire B
I_b = V / R_b
I_b = V / Ro
wire
I_a = V / R_a
I_a = V / 4 Ro
I_a = ¼ I_a
5 is false