Answer:
It would no longer be a polar molecule with a slightly positive and slightly negative ends. It then would not be able to dissolve ionic salts or polarized organic compounds such as sugar.
Explanation:
Answer is B. gas formation
Your answer is probably
Vaporization point
Answer:
(2R,3S)-2-ethoxy-3-methylpentane
and
(2S,3S)-2-ethoxy-3-methylpentane
Explanation:
For this case, we will have
as nucleophile. Also, this compound is also in excess. So, we will have as solvent
a protic solvent. Therefore the Sn1 reaction would be favored.
The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).
Explanation:
elements are based on electrical conductivity