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Wewaii [24]
4 years ago
12

A force of 250 N is applied to an object that accelerates at a rate of 10m/sec2. What is the mass of the object?

Physics
1 answer:
Mrac [35]4 years ago
4 0
F=ma. So if you have the Force and the Acceleration you can find the mass. m=F/a. So the mass is 25kg
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Answer:

The volume of the submerged part of her body is 0.0622m^{3}

Explanation:

Let's define the buoyant force acting on a submerged object.

In a submerged object acts a buoyant force which can be calculated as :

B=ρ.V.g

Where ''B'' is the buoyant force

Where ''ρ'' is the density of the fluid

Where ''V'' is the submerged volume of the object

Where ''g'' is the acceleration due to gravity

Because the girl is floating we can state that the weight of the girl is equal to the buoyant force.

We can write :

W_{girl}=B (I)

Where ''W'' is weight

⇒ If we consider ρ = 1000\frac{kg}{m^{3}} (water density) and g=9.81\frac{m}{s^{2}} and replacing this values in the equation (I) ⇒

B=W_{girl}

B=610N

ρ.V.g = 610N

1000\frac{kg}{m^{3}}.V.(9.81\frac{m}{s^{2}})=610N (II)

The force unit ''N'' (Newton) is defined as

N=kg.\frac{m}{s^{2}}

Using this in the equation (II) :

(9810\frac{N}{m^{3}}).V =610N

V=\frac{610N}{9810\frac{N}{m^{3}}}

V=0.0622m^{3}

We find that the volume of the submerged part of her body is 0.0622m^{3}

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There are 3.3V passing through an orange power supply cable, and there are 0.025 ohms of resistance in the orange wire. How much
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P = V^2 / R.

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Substituting V/R in for I in the 1st equation, you get P = V^2 / R.
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