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Ksivusya [100]
3 years ago
5

Consider two wind turbines, each located in sites with the same wind speed, and each with the same efficiency. Turbine 1 has a r

adius of 25 meters. Turbine 2 has a radius of 50 meters. Turbine 2 generates ___ times as much power as turbine 1. (Fill in the blank.)
Physics
1 answer:
Alex787 [66]3 years ago
7 0

Answer:

shut up nerd

Exption:

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A 2.0kg rock is thrown straight up into the air with a speed of 30m/s. Ignore air resistance. What is the net force acting on th
bazaltina [42]

Answer:

19.6N

Explanation:

Given parameters:

Mass of rock = 2kg

Speed  = 30m/s

Unknown:

Net force on the rock  = ?

Solution:

The net force acting on this rock is a function of the acceleration due to gravity acting upon it.

 Net force  = weight  = mass x acceleration due to gravity

 Net force  = 2 x 9.8  = 19.6N downward

6 0
2 years ago
A 235 kg motorcycle moves with a velocity of 7 m/s. What's it's kenetic energy?
antiseptic1488 [7]
The non-relativistic formula for low speed  v < 0.1c is:

K.E = 0.5mv^2 = 0.5 * 235 * (7)^2 = 5757.5 J
7 0
3 years ago
A 6,000N is applied to a formula one car that weighs 500kg. What is the car's acceleration?
Vesna [10]

Answer:

<h2>12 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question

f = 6000 N

m = 500 kg

We have

a =  \frac{6000}{500}  =  \frac{60}{5}  = 12 \\

We have the final answer as

<h3>12 m/s²</h3>

Hope this helps you

8 0
2 years ago
How did Bourne believe that an object could be made to rise or sink at will?
Angelina_Jolie [31]
Bourne believed that an object would float or sink at will as long as he could <span>manipulate the effect's of buoyancy which control and object to sink or float. Hope this helps!

</span>
4 0
3 years ago
Read 2 more answers
What is the law of variation of the period T of a simple pendulum
DIA [1.3K]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum and g=9.81 m/s^2 is the gravitational acceleration. As we can see, the period of a simple pendulum depends only on its length.
3 0
3 years ago
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