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Gwar [14]
3 years ago
12

What is not an ethical concern that psychological researchers must consider?

Physics
1 answer:
natita [175]3 years ago
4 0

the answer is A privacy + confidentiality of personal info for up to 10 years.

Explanation:

i took the quiz

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What is the arrangement of the forms of electromagnetic radiation according to their wavelengths?
Svetradugi [14.3K]
Gamma rays then x rays then UVA rays then visible light then IR then radio waves (from highest to lowest frequency).
6 0
3 years ago
A magnetic B field of strength 0.9 T is perpendicular to a loop with an area of 3 m2. If the area of the loop is reduced to zero
Alexeev081 [22]

Answer:

The magnitude of induced emf is 5.4 V

Explanation:

Given:

Magnetic field B = 0.9 T

Area of loop \Delta A = 3 m^{2}

Time take to reduce loop to zero \Delta t = 0.5 sec

To find induced emf we use faraday's law,

Induced emf is given by,

  \epsilon = -\frac{\Delta \phi}{\Delta t}

Here minus sign shows lenz law, for finding magnitude of emf  we ignore it.

Where \phi = B\Delta A

Put the value of flux and find induced emf,

   \epsilon = \frac{B\Delta A}{\Delta t}

   \epsilon = \frac{0.9 \times 3}{0.5}

   \epsilon = 5.4 V

Therefore, the magnitude of induced emf is 5.4 V

3 0
3 years ago
What do scientists use to determine the temperature of a star?
Nastasia [14]

Answer:

Measure the brightness of a star through two filters and compare the ratio of red to blue light. Compare to the spectra of computer models of stellar spectra of different temperature and develop an accurate color-temperature relation.

7 0
3 years ago
Two long, parallel wires carry unequal currents in the same direction. The ratio of the currents is 3 to 1. The magnitude of the
astraxan [27]

Answer:

3A is the larger of the two currents.

Explanation:

Let the currents in the two wires be I₁ and I₂

given:

Magnitude of the electric field, B = 4.0μT = 4.0×10⁻⁶T

Distance, R = 10cm = 0.1m

Ratio of the current = I₁ : I₂ = 3 : 1

Now, the magnitude of a magnetic field at a distance 'R' due to the current 'I' is given as

B = \frac{\mu_oI}{2\pi R}

Where \mu_o is the magnitude constant = 4π×10⁻⁷ H/m

Thus, the magnitude of a magnetic field due to I₁ will be

B_1 = \frac{\mu_oI_1}{2\pi R}

B_2 = \frac{\mu_oI_2}{2\pi R}

given,

B = B₁ - B₂ (since both the currents are in the same direction and parallel)

substituting the values of B, B₁ and B₂

we get

4.0×10⁻⁶T =  \frac{\mu_oI_1}{2\pi R} - \frac{\mu_oI_2}{2\pi R}

or

4.0×10⁻⁶T =  \frac{\mu_o}{2\pi R}\times (I_1-I_2 )

also

\frac{I_1}{I_2} = \frac{3}{1}

⇒I_1 = 3\times I_2

substituting the values in the above equation we get

4.0×10⁻⁶T =  \frac{4\pi\times 10^{-7}}{2\pi 0.1}\times (3 I_2-I_2)

⇒I_2 = 1A

also

I_1 = 3\times I_2

⇒I_1 = 3\times 1A

⇒I_1 = 3A

Hence, the larger of the two currents is 3A

3 0
3 years ago
Please help meh
bezimeni [28]

Answer:

A : the handle will be hot because metal is a good conductor of heat

Explanation:

B The handle will be slippery because metal is slippery when heated. - there is no evidence of this literally anywhere lol

C The handle will be soft because the metal in cooking pans is easily melted. - cast irons melting degree is 1204°C, so unless your cooking lava or something the handle is not gonna melt

D The handle will be freezing cold because metal turns heat to cold. - No, because the containments of the pot are hot not cold, and metal conducts heat

4 0
2 years ago
Read 2 more answers
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