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3 years ago

If a spear is jabbed exactly at that place where the fish appears in water, the fish is not killed. Give reason

Physics

2 answers:

murzikaleks [220]3 years ago

7 0

Answer:

The fish is not killed due to the Refraction (bending) of light.

Explanation:

The light experiences a phenomenon called Refraction that is the change of path or bending. As light travels from denser medium (water) to a less dense medium (air), its speed increases to some extent. Due to this change in speed of light, the path of the light changes. The observer sees the image of fish in the water formed by these bent rays of light coming off the fish which is at a different location and he/she jabs the spear at that location. However, as it is not the real location of fish but how it appears due to refraction, the spear is jabbed at a wrong location and the fish is not killed.

Anestetic [448]3 years ago

3 0

Source:

ARC Centre of Excellence in Coral Reef Studies

Summary:

Fish are not as dumb as people sometimes think. Marine scientists have found that fish that are regularly hunted with spearguns are much more wary and keep their distance from fishers. In investigating the effects of marine areas closed to fishing by customary laws, an international team of researchers working in the Pacific found that fish exposed to speargun fishing take flight much earlier when a diver approaches compared with those living in protected zones.

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Answer:

They measured their train using their handspan

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3 years ago

A 405 Hz tuning fork and a piano key are struck together, and no beats are heard. When a 402 Hz tuning fork and the same piano k

NeX [460]

The difference between the frequencies of the piano key and the tuning fork gives the frequency of the beats.

When the tuning fork is 405 Hz, and no beats are heard, then the piano key is also 405 Hz.

When the piano key is 405 Hz and the tuning fork is 402 Hz, then 405 - 402 = 3 beats are heard.

The piano key is 405 Hz.

4 0

4 years ago

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bija089 [108]

Answer:

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Explanation:

In order for Tom to successfully complete the marathon, he should focus on being able to maintain a constant pace without tiring easily.

3 0

4 years ago

Unpolarized light is incident upon two polarization filters that do not have their transmission axes aligned. If 21% of the ligh

Debora [2.8K]

Answer:

49.6°

Explanation:

$I_0$ = Unpolarized light

$I_2$ = Light after passing though second filter = $0.21I_0$

Polarized light passing through first filter

$I_1=\frac{I_0}{2}$

Polarized light passing through second filter

$I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.21I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.21I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.21I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.21\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.42}\\\Rightarrow \theta=49.6^{\circ}$

The angle between the two filters is 49.6°

5 0

4 years ago

Light travels through a liquid at 2.25e8 m/s. What is the index of refraction of the liquid?

Pavlova-9 [17]

Answer:

The index of refraction of the liquid is n = 1.33 equivalent to that of water

Explanation:

Solution:-

- The index of refraction of light in a medium ( n ) determines the degree of "bending" of light in that medium.

- The index of refraction is material property and proportional to density of the material.

- The denser the material the slower the light will move through associated with considerable diffraction angles.

- The lighter the material the faster the light pass through the material without being diffracted as much.

- So, in the other words index of refraction can be expressed as how fast or slow light passes through a medium.

- The reference of comparison of how fast or slow the light is the value of c = 3.0*10^8 m/s i.e speed of light in vacuum or also assumed to be the case for air.

- so we can mathematically express the index of refraction as a ratio of light speed in the material specified and speed of light.

- The light passes through a liquid with speed v = 2.25*10^8 m/s :

$n = c / v\\\\n = \frac{ 3*10^8 }{2.25*10^8} \\\\n = 1.33$

- The index of refraction of the liquid is n = 1.33 equivalent to that of water.

8 0

3 years ago

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