Answer:
It can't be done.
Explanation:
If you have only 5.4 g of oxygen, the most lithium oxide you can get is 7.7 g.
Only 2.3 g of lithium will react. and the other 22.3 g of lithium will not be used.
x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points
f(x)=x+2−x^2
df/dx=1–2x
and that is zero (indicating a maximum) at x=1/2
So the maximum distance is f(1/2)=2.5–0.25=2.25
learn more about maximum distance between curves here:
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When alpha decay takes place, two protons and two neutrons are forcefully ejected from the nucleus in a way that looks very similar to a Helium nucleus. This type of decay causes the atomic mass of the parent particle to drop by four (four particles lost), but the atomic number drops by only two (two protons lost). Therefore, your answer is C.
52 g of hydrogen H₂
Explanation:
I will assume that the problem is talking about the hydrogenation of carbon dioxide CO₂ not carbon monoxide CO. It is harder to reduce carbon dioxide than carbon monoxide and if you manage to reduce carbon dioxide you can reduce the carbon monoxide as well.
This reaction it will take place in the presence of catalyst at a specific temperature and pressure.
CO₂ + 4 H₂ → CH₄ + 2 H₂O
Now taking into the account the chemical reaction we devise the following reasoning:
if 1 mole of CO₂ react with 4 moles of H₂
then 6.5 moles of CO₂ react with X moles of H₂
X = (6.5 × 4) / 1 = 26 moles of H₂
number of moles = mass / molecular wight
mass = number of moles × molecular wight
mass of H₂ = 26 × 2 = 52 g
Learn more about:
hydrogenation reaction
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