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Studentka2010 [4]
3 years ago
5

What two structures would provide a positive identification of a plant cell under a microscope? a)cell wall, mitochondria b)plas

ma membrane, large central vacuole c)ribosomes, chloroplasts d)cell wall, chloroplast
Chemistry
2 answers:
lutik1710 [3]3 years ago
6 0

<h2>Answer:</h2>

The correct answer is option D which is cell wall, chloroplast.

<h3>Explanation:</h3>
  • Here positive identification means such features in plant cell which are significantly distinguishes plant cell from animals cells.
  • Cell wall is outer envelope type structure present around the cell membrane. It is not present in animal cells.
  • Chloroplasts are plasmids. These organelles are distinguished structure of photosynthesizing cells.
  • Hence only plant cells have chloroplast while chloroplast are absent i animal cells.
  • So from looking at chloroplast and cell wall we can identify a plant cell.
olga55 [171]3 years ago
3 0

Cell wall, Large central vacuole, Chloroplasts

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3 years ago
g A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is __________ compared to a 300 mOsM sol
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A solution contains 100mM NaCl, 20mM CaCl2, and 20mM urea. We would say this solution is hypotonic compared to a 300 mOsM solution and hypotonic compared to a cell with 300 mOsM (non-penetrating solutes) interior.

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The osmolarity is calculated from the molar concentration of the active particles in the solution. We have a solution that is composed of NaCl, CaCl₂ and urea.

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NaCl → Na⁺ + Cl⁻  (2 particles per compound)

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urea: not dissociation (1 particle per compound)

Then, we have to calculate the osmolarity of the solution. We multiply the molarity of each compound by the number of particles produced by the compound in water:

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Compared with 300 mOsm, 280 mOsm has a lower osmolarity, so it is a hypotonic solution.

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4 0
3 years ago
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
barxatty [35]

Answer: 353.6 g.


Explanation:


1) Word equation (given)

Sodium phosphate + calcium choride → sodium chloride + calcium phosphate


2) Balanced chemical equation

2 Na₃PO₄ +3 CaCl₂ → 6 NaCl + Ca₃(PO4)₂


3) Mole ratio

2 moles Na₃PO₄ : 3 moles CaCl₂ :  6 moles NaCl : 1 mole Ca₃(PO4)₂


4)  Formula to convert grams to moles

number of moles = mass in grams / molar mass


5) Number of moles of limiting reactant

a) mass in grams = 379.4 g CaCl₂

b) molar mass CaCl₂ = 110.98 g/mol

c) number of moles CaCl₂ = 379.4 g / 110.98 g/mol = 3.419 moles


6) Theoretical yield of Ca₃(PO4)₂

    3 moles CaCl₂ / 1 mole Ca₃(PO4)₂ = 3.419 moles CaCl₂ / x ⇒

    x = 3.419 × 1 / 3 = 1.140 moles Ca₃(PO4)₂


7) Convert 1.140 moles Ca₃(PO4)₂

a) molar mass Ca₃(PO4)₂ = 310.1767 g/mol

b) mass in grams = number of moles × molar mass = 1.140 moles × 310.1767 g/mol = 353.6 g ← answer.

7 0
3 years ago
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