3 years ago

What is the mass of 0.75 moles of (NH4)3PO4?

Chemistry

2 answers:

Tomtit [17]3 years ago

8 0

Answer:

well it turns into N3H12PO4

Explanation:

nikklg [1K]3 years ago

3 0

It’s is (nh4)3po4 that would be your answer

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Which best describes nuclear fission?

rewona [7]

Answer:

C. The splitting apart of atomic nuclei

Explanation:

Nuclear fission is the splitting apart of atomic nuclei.

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2 years ago

The compound gallium phosphide () is a compound semiconductor having mixed ionic and covalent bonding. The electronegativities f

9966 [12]

Answer:

$0.08875$

Explanation:

Hello,

In this case, the first step is to compute the difference in the electronegativity for the formed bond between gallium and phosphorous by:

$\Delta E=2.1-1.6\\\\\Delta E=0.5$

Thus, we can compute the percentage of ionic character by:

$\%\ ionic\ character=16\Delta E +3.5 (\Delta E)^2\\\\\%\ ionic\ character=16*0.5+3.5*0.5^2\\\\\%\ ionic\ character=8.875\%$

So the fraction is just:

$\frac{8.875}{100}=0.08875$

Which has sense since gallium phosphide is a non-polar compound.

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3 years ago

Which are the nutrients essential to us

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Explanation:

carbohydrate,fat,protein, vitamin, mineral, water

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3 years ago

Read 2 more answers

Look at the diagram. What number needs to be added to balance the equation?

suter [353]

Answer:

Explanation:

because hydrogen is a diatomic element, so it can't be just H

4 0

2 years ago

If an automobile air bag has a volume of 11.7 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact

Usimov [2.4K]

Answer:

33.95 grams of NaN3

Explanation:

Number of moles of NaN3 = mass (m)/MW = m/65 mole

I mole of NaN3 requires 22.4L air bag

m/65 mole of NaN3 required 11.7L

22.4m/65 = 11.7

22.4m = 65×11.7

22.4m = 760.5

m = 760.5/22.4 = 33.95grams of NaN3

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2 years ago