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Black_prince [1.1K]
3 years ago
8

Imagine that you started from 5.00 grams of BaCl2.2H2O, which is your limiting reactant. If only 70% of BaCl2.2H2O gives the des

ired product, 18% results in BaHPO4 and the rest of BaCl2.2H2O is converted into the other side product, calculate the hypothetical percent yield based on the assumption that Ba3(PO4)2 is the only product.

Chemistry
1 answer:
torisob [31]3 years ago
4 0

Answer:

Following is attached the solution for given question.

i hope it will help you a lot!

Explanation:

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An object has a mass of 72 kg. What is its weight?
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Explanation:

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Calculate the number of molecules in 7 moles of oxygen
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4.21

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3 years ago
Grady is doing an experiment about the solubility of sugar. He puts 100 milliliters of water in each of three beakers. He leaves
olga nikolaevna [1]

Grady is doing an experiment about the solubility of sugar. He puts 100 milliliters of water in each of three beakers. He leaves the first beaker at room temperature, heats the second beaker to 60°C, and heats the third beaker until the water boils at 100°C. The variable Grady change on  purpose in the experiment is the temperature of water in each beaker .

Variables in the experiment is the any factor that can exist in different types or amount. There are three types of variables: independent variable , dependent variable , controlled variable. The independent variable is the variable you changed in the experiment. dependent variable is that changes because of independent variable. the controlled variable is the constant one.

Thus, Grady is doing an experiment about the solubility of sugar. He puts 100 milliliters of water in each of three beakers. He leaves the first beaker at room temperature, heats the second beaker to 60°C, and heats the third beaker until the water boils at 100°C. The variable Grady change on  purpose in the experiment is the temperature of water in each beaker .

To learn more about variables here

brainly.com/question/17344045

#SPJ1

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Which metal will lose electrons more easily, Ca or Mg?
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