Imagine that you started from 5.00 grams of BaCl2.2H2O, which is your limiting reactant. If only 70% of BaCl2.2H2O gives the des
ired product, 18% results in BaHPO4 and the rest of BaCl2.2H2O is converted into the other side product, calculate the hypothetical percent yield based on the assumption that Ba3(PO4)2 is the only product.
1 mol of ideal gas at STP occupies 22.4 (or 22.7 depending on the convention being used for STP) liters in volume. I will use 22.4 so 17.88*22.4 = 400.5 L