dilution
V₁M₁=V₂M₂
V₁.12 = 100.6
V₁=50 ml
Add water 50 ml to 50 ml 12 M
Answer:
B) CH3CH2CH2F
Explanation:
All the other compounds listed among the options are capable of forming hydrogen bonds with water except CH3CH2CH2F.
Recall that hydrogen bonds are formed when hydrogen is directly bonded to a highly electronegative atom such as nitrogen, oxygen, fluorine, sulphur, et cetra.
Such bonds are not present in CH3CH2CH2F, rather fluorine is bonded to carbon to give a halogenoalkane. This compound will display the least solubility in water.
<span>2LiBr + Cl2 → 2LiCl + Br<span>2
Lithium Bromide + Chlorine</span></span>
