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4 years ago

How are distillation and reverse osmosis alike?

1 answer:

5 0

I'm having trouble with this one. At the very least, they both purify water. If I'm not mistaken, distillation is part of the process of purifying water.
Really sorry, I hope I helped at least a little! If you have any other questions I might be able to answer better, let me know..

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Which of the following has kinetic energy?

Molodets [167]

Answer:

c ) a gymnast doing a cartwheel. ........

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3 0

3 years ago

Read 2 more answers

What is the concentration of a 0.750 l solution that contains 52.0 g of glucose (c6h12o6)?

vodka [1.7K]

Concentration of Solutions is oftenly expressed in Molarity. Molarity is the number of moles of solute dissolved per volume of solution.

Molarity = Moles / Volume
As,
Moles = Mass / M.mass
So,
Molarity = Mass / M.mass × Volume ---- (1)

Data Given;
Volume = 0.750 L

Mass = 52 g

M.mass = 180 g/mol

Putting Values in eq.1,

Molarity = 52 g ÷ (180 g.mol⁻¹ × 0.750 L)

Molarity = 0.385 mol.L⁻¹

7 0

3 years ago

Which sphere is dependent on all the other spheres in order to exist?

egoroff_w [7]

Answer:

biosphere

Explanation:

Living things need water (hydrosphere), chemicals from the atmosphere, and nutrients gained by eating things in the biosphere.

6 0

3 years ago

Under which conditions do you expect helium gas to deviate most from ideal behavior?. . a. 100 K and 1 atm. b. 300 K and 2 atm.

mamaluj [8]

Ideal behavior is approached by gases when the conditions of the system are at a low pressure and high temperatures. Therefore, the correct answer is C. At the conditions of lowest temperature highest pressure, gases will deviate from an ideal gas.

3 0

4 years ago

A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio

MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758 grams

Thus, the percent yield for this reaction = $\frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100$

the percent yield for this reaction = $\frac{0.53}{0.5758}\times100$

the percent yield for this reaction = 92.04%

6 0

3 years ago