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mezya [45]
3 years ago
12

Two different recording stations have found that they had the same value for ΔT after an earthquake. If this is all the informat

ion they have so far, what can they conclude?
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

The epicenter is the same distance from both recording stations

Explanation:

ΔT is the time between anomaly occurrence and the origin time of the earthquake.

Now, we are told both stations had the same value for ΔT.

This means that their points on the earth's surface which vertically above the focus of the earthquake is the same and thus we can conclude that the epicenter is the same distance from both stations.

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I have a buddy who recycles electronics, and isolates metals from the connector pins electrical boards. He isolates gold, for ex
bogdanovich [222]

Solution :

In the process to isolate gold that has a 80 percent yield, a 3.00 g of Au is being isolated.

That is, the actual yield of Au is 3. 00 g

Therefore, we need to find the theoretical yield.

As we know,

$\text{percent yield}=\frac{\text{actual yield}}{\text{theoretical yield}} \times 100$

$\text{theoretical yield}=\frac{\text{actual yield}}{\text{present yield}} \times 100$

As actual yield = 3.00 g

    percent yield = 80 %

So, theoretical yield = $\frac{3.00}{80} \times 100$

                                  = 3.75 g

Thus he should be able to get 3.75 g which is the theoretical yield of Au.

5 0
3 years ago
Which procedure(s) decrease(s) the random error of a measurement:
PolarNik [594]

Taking the average of more measurements decreases random error of measurement

Taking the average of many measurements is the most effective way to reduce random errors in a measurement. Because the certainty of the results grows as the number of data does, Less risk of random errors means that the value is more certain. Fewer measurements lead to less reliable data collection, which raises the likelihood of random errors.

The complete question is

Which procedure(s) decrease(s) the random error of a measurement: (1) taking the average of more measurements: (2) calibrating the instrument; (3) taking fewer measurements? Explain

To learn more about random errors:

brainly.com/question/14149934

#SPJ4

8 0
2 years ago
Rachel burns a 53 gram cracker under a soda can filled with 81.6 grams of water. She took the temperature of the water before sh
Anna11 [10]

Answer

Q=4479.8 cal

Procedure

To solve the problem you will need to use the specific heat formula

Q=mc\Delta T

Where;

Q=heat energy

m=mass

c=specific heat capacity

ΔT=change in temperature

Assuming that the heat released from the cracker of unknown material is equal to the heat absorbed by the water, then we can use the c and m for water in our calculations.

c_{water}=4.186\frac{J}{g\degree C}

Substituting the values in our equation we have

Q=mc\Delta T=81.6\text{ }g(4.186\frac{J}{g\degree C})(68.1-13.2)\degree C=18752.61\text{ }J

Finally, transform the J to cal

18752.61\text{ }J\frac{1\text{ }cal}{4.186\text{ }J}=4479.8\text{ cal}

8 0
1 year ago
How many kilojoules are needed to raise the temperature of 234 g of water from 19.8 C to 33.1 C?
xenn [34]

Answer:

13 kJ

Explanation:

Use the following formula where Q is the Joules needed, m is the mass of the substance, c is the heat capacity, and ΔT is the change in temperature.

Q = mcΔT

The heat capacity of water is 4.186 J/g°C.  The mass of water is 234 g.  The change in temperature is 13.3°C.

Q = mcΔT

Q = (234 g)(4.186 J/g°C)(13.3°C)

Q = 13,027 J

Since the answer is in Joules, convert to kiloJoules.

13,027 J  =  13.027 kJ  ≈  13 kJ

5 0
4 years ago
Sodium hydroxide is added to many swimming pools to neutralize excess acidity from hydrochloric acid (which is a solution of hyd
Gnom [1K]
Hope this helps you!

7 0
3 years ago
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