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aliina [53]
3 years ago
15

Which diagram best illustrates the difference between distance and displacement?

Chemistry
1 answer:
olga nikolaevna [1]3 years ago
5 0

Answer:

B

Explanation:

not sure

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Find the pH of a solution that has an H+ concentration of 2.5x10-3 M
Nastasia [14]

Answer:

The pH is 2, 60

Explanation:

The pH gives us an idea of the acidity or basicity of a solution. It is calculated as:

pH = -log (H +)= -log (2.5x10-3 )

<em>pH=2, 60</em>

7 0
3 years ago
Which of the following best describes an electron?
GenaCL600 [577]
B. It has a negative charge and much less mass than a proton. 
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3 years ago
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Which of the above electron dot diagrams is wrong and why?
Elodia [21]

Answer:

Oxygen, it's supposed to have six valenge electrons.

Explanation:

Count the dots on the oxygen atom, you'll see seven, but there's supposed to be six.

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3 years ago
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Calculate the equilibrium constant k for the isomerization of glucose-1-phosphate to fructose-6-phosphate at 298 k. express your
k0ka [10]
We cannot solve this problem without using empirical data. These reactions have already been experimented by scientists. The standard Gibb's free energy, ΔG°, (occurring in standard temperature of 298 Kelvin) are already reported in various literature. These are the known ΔG° for the appropriate reactions.

<span>glucose-1-phosphate⟶glucose-6-phosphate          ΔG∘=−7.28 kJ/mol
fructose-6-phosphate⟶glucose-6-phosphate          ΔG∘=−1.67 kJ/mol
</span>
Therefore, the reaction is a two-step process wherein glucose-6-phosphate is the intermediate product.

glucose-1-phosphate⟶glucose-6-phosphate⟶fructose-6-phosphate 

In this case, you simply add the ΔG°. However, since we need the reverse of the second reaction to end up with the terminal product, fructose-6-phosphate, you'll have to take the opposite sign of ΔG°.

ΔG°,total = −7.28 kJ/mol  + 1.67 kJ/mol = -5.61 kJ/mol

Then, the equation to relate ΔG° to the equilibrium constant K is

ΔG° = -RTlnK, where R is the gas constant equal to 0.008317 kJ/mol-K.
-5.61 kJ./mol = -(0.008317 kJ/mol-K)(298 K)(lnK)
lnK = 2.2635
K = e^2.2635
K = 9.62


6 0
3 years ago
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Which is TRUE about intermolecular
lbvjy [14]

Answer:

They are Weaker than a chemical

<h2>bond</h2>

corrected by the one in the comment section

5 0
3 years ago
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