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kramer
4 years ago
10

What determines the type of the image formed after refraction from a convex lens?

Physics
2 answers:
saw5 [17]4 years ago
8 0
C. position of the object
Hope it helps! :)
faust18 [17]4 years ago
5 0

Answer:

option (c)

Explanation:

A convex lens produces a real image of an object when placed beyond focus.

It produce virtual image when object placed between focus and pole.

So, the position of the object decides the type of image formed.

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What is the velocity of a car if it travels east 340 meters in 10 seconds? V = d/t
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Ignoring air​ resistance, an object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic mode
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Given that,

An object in free fall will fall d feet in t​ seconds, where d and t are related by the algebraic model as :

d=16t^2..........(1)

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16t^2=1148

t=\sqrt{71.75}

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7 0
4 years ago
The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc
ZanzabumX [31]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = V_{f}^{2}-V_{i}^{2}

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr =  54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

6 0
3 years ago
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