Question

A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?

Answer 1

Work done = force * distance moved (in direction of the force)

force= mass* acceleration 

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J

Answer 2

The correct answer to the question is $336.98\times 10^4\ J$

CALCULATION:

The acceleration of the truck is given as a = $0.0083\ m/s^2$

The mass of truck is given as m = 7000 kg.

The distance travelled by the truck S = $5.8\times 10^{4}\ m$.

The force applied on the truck is calculated as -

                            Force F = mass × acceleration

                                      = $7000\ kg\times 0.0083\ m/s^2$

                                      = 58.1 N.

We are asked to calculate the work done .

The work done by a body is calculated as -

                                              W = $\vec F.\vec S$

                                                   = $FScos\theta$

Here, $\theta$ is the angle between force and displacement.

If $\theta=0^{0}$, then W = FS

Hence, the work done by the truck W = FS

                                                               = $58.1\ N\times 5.8\times 10^{4}\ m$

                                                               = $336.98\times 10^4\ J$

Here, J ( joule ) is the unit of work.