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Ivan
3 years ago
5

Engineers design for everyone and consider all design challenges opportunities to problem-solve. The roller coaster in this phot

o is the largest wooden coaster in East China. It stands 32 meters tall, 1,060 meters long, and is capable of speeds of up to 91 kilometers per hour. Is the need to build a roller coaster should be considered an engineering design problem?
Engineering
1 answer:
AlexFokin [52]3 years ago
5 0

Answer:

No

Explanation:

The "need" to build a roller coaster would not be considered an engineering design problem. This would be more of a management/accounting problem because they are the ones that analyze numbers and decide what the amusement park would need in order to maintain/increase profitability by attracting more customers. Therefore, if they "need" a new roller coaster to do so then it becomes their problem. For it to be an engineering design problem the statement should be "the need to design a roller coaster with certain specifics" or something along those lines.

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Explanation:

For explanation, look at the attached file

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The "view factor" Fij depends on surface emissivity and surface geometry. a) True b) False
Alex

Answer:

(B) FALSE

Explanation:

view factor F_{ij} depends on the surface emissivity and the surface of geometry  view factor is the term used in radiative heat transfer. View factor is depends upon the radiation which leave the surface and strike the surface.View factor is also called shape factor configuration factor it is denoted by  F_{ij}

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What is the purpose of the graphic language?
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3 years ago
While supporting load P, the maximum contraction permitted in a 4.75-m long pipe column is 7 mm. Given that E =180 GPa for the c
Alexeev081 [22]

Answer:

\mathbf{stress \ \sigma = 264.6 \ Mpa}

Explanation:

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E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

where;

strain \ \varepsilon = \dfrac{change \ in \ dimension }{original \ dimension}

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strain \ \varepsilon =0.00147368

Recall:

E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

stress \ \sigma = E \times { strain \  \varepsilon}

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3 years ago
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