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Airida [17]
3 years ago
12

Water flows through two smooth pipes with the same diameter and length as shown below. ipe is twice that through the first-pipe.

Both flows are The flow rate through the s laminar and fully _developed. Circle the letter of the statement that is correct about the pressure drop (pressure difference over the pipe length). (a) Pipe 1 has the higher pressure drop. (b) Pipe 2 has the higher pressure drop. (c) Pipes 1 and 2 have the same pressure drop. (d) T here is not enough information to answer the question.
Engineering
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

The right answer is (d)

Explanation:

The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones

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For the same cross-sectional area, which column provides the higher buckling load: a circular bar or a circular tube?
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Circular tube

Explanation:

Now for better understanding lets take an example

Lets take

Diameter of solid bar= 4\sqrt{2} cm

Outer diameter of tube =6 cm

Inner diameter of tube=2 cm

So from we can say that both tubes have equal cross sectional area.

We know that buckling load is given as P = \dfrac{\pi ^2EI}{L_e^2}      

If area moment of inertia(I) is high then buckling load will be high.

We know that  area moment of inertia(I)

For circular tube I = \dfrac{\pi }{64}(D_o^4-D_i^4)

For circular bar I = \dfrac{\pi }{64}D^4  

Now by putting the values

    For circular tube I=62.83 cm^4

  For circular bar I=50.26 cm^4

So we can say that for same cross sectional area the  area moment of inertia(I) is high for tube as compare to bar.So buckling load  will be higher in tube as compare to bar.

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Amplifiers are extensively used in the baseband portion of a radio receiver system to condition the baseband signal to produce a
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5 0
3 years ago
Compact fluorescent bulbs are much more efficient at producing light than are ordinary incandescent bulbs. They initially cost m
Ilia_Sergeevich [38]

Answer:

ordinary bulb total cost is $39.54

fluorescent bulb total cost is $13.05

amount save = 39.54 - 13.05 = $26.49

resistance = 626.1 ohm

Explanation:

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cost of operation = $35.04

so total cost will be = $4.5 + $35.04  = $39.54

and

when compare with florescent bulb

time = 3 year = 4380 h

life of bulb = 10000 h

so number of bulb required = \frac{4380}{10000}

number of bulb required = 0.43 = 1

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so

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in part 2nd

total amount save while compare bulb is

amount save = 39.54 - 13.05 = $26.49

and in part 3rd

resistance of bulb is

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resistance = \frac{120^2}{23}

resistance = 626.1 ohm

6 0
3 years ago
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