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3 years ago

If Andrew has $72 in his wallet, what is the largest number of bags of sugar he can afford? (Each bag of sugar costs $6.33)

Mathematics

2 answers:

aleksklad [387]3 years ago

8 0

Answer:

11 bags

Step-by-step explanation:

$72/6.33=11.3744075829 or 11.4

11.4 estimate= 11

Sav [38]3 years ago

7 0

Answer:

11 bags of sugar

Step-by-step explanation:

In order to find the answer to this question simply divide the amount of money Andrew has by the amount of money it cost per bag of sugar.

$S=6.33$

$W=72$

$72\div6.33=11.3744075829$

Round:

$=11$

Hope this helps.

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Please help me this looks easy but I don’t understand it tho

Tems11 [23]

Let's call the unknown amount of money x

Betty spend 5/12 of her money (5/12)x and had 42 dollars left. Translated,

$x - \frac 5{12} x = 42$

Solving,

$x(1 - \frac 5{12}) = 42$

$\frac{7}{12} x = 42$

$x = \dfrac{12}{7} \cdot 42 = 72$

Answer: $72

4 0

3 years ago

What are the measurements of the little 2 small cube things on each side, better yet what's the surface area? Thank you

Arisa [49]

Answer:

166 units²

Step-by-step explanation:

We know that:

W = 7
L = 5
H = 4

Surface area is the area of the faces of the cuboid.

Work:

=> 2(7 x 4) + 2(5 x 4) + 2(5 x 7)
=> 2(28) + 2(20) + 2(35)
=> 56 + 40 + 70
=> 166 units²

Hence, Option C is correct.

Hoped this helped.

$BrainiacUser1357$

4 0

2 years ago

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e-lub [12.9K]

Answer:

Step-by-step explanation:

In order to determine the information you're being asked for, you need to complete the square on that quadratic. The first step is to move the constant over to the other side of the equals sign:

$x^2-2x=3$

Here would be the step where, if the leading coefficient isn't a 1, you'd factor it out. But ours is a 1, so we're good there. Now take half the linear term (the term with the single x on it), square it, and add it to both sides. Our linear term is a -2. Half of -2 is -1, and -1 squared is +1. We add +1 to both sides giving us this:

$x^2-2x+1=3+1$

Now we'll clean it up a bit. The right side becomes a 4, and the left side is written as its perfect square binomial, which is the whole reason we did this. That binomial is

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