A capacitor is connected to an ac supply. increasing the frequency of the supply increases the current through the capacitor
A capacitor is a device for storing electrical energy that consists of two insulated conductors in close proximity. The parallel-plate capacitor is a simple example of such a storage device.
A capacitor (also known as a condenser) is a two-terminal passive electrical component that stores energy electrostatically in an electric field. Practical capacitors come in a variety of shapes and sizes, but they all have at least two electrical conductors (plates) separated by a dielectric (i.e., insulator).
Capacitors exist in various shapes and sizes, and their value is measured in farads (F). Capacitors are utilized in both alternating current and direct current systems.
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To solve this we can use one of the main four kinematic equations, preferably we want something that we can use directly without solving for other values.
So in this problem we know that:
Inital velocity or Vi = 0 (started from rest)
The acceleration of the object = 7.5
The distance the object travels Δx = 87m
So, our best equation here with what we have would be:
Vf² = Vi² + 2aΔx
Now we now that Vi is 0 so:
Vf² = 2aΔx
We need final velocity so lets take the square root of Vf to isolate it:
Vf = √2aΔx
Now we plug in
Vf = √2(7.5)(87)
Vf = 36.124 m/s or 36.1 m/s
Answer:
<em>58,800Joules</em>
Explanation:
The energy lost is equal to the workdone by the car as it skids.
Workdone = Force * Distance
Given
Force = 8000N
Get the distance using the equation of motion
v² = u² - 2gS
0² = 12² - 2(9.8)S
-12² = - 2(9.8)S
-144 = -19.6S
S = 144/19.6
S = 7.35m
Calculate the required energy
Workdone = 8000 * 7.35
Workdone = 58,800Joules
<em>Hence the energy lost due to friction is 58,800Joules</em>
Answer:
Assuming that gravity has not caused the ball to start falling then after 2.5 seconds the ball will be 37.5 meters in the air
Explanation:
The ball travels 15 meters every second so for 2 seconds we would multiply 15*2=30. We have 2.5 seconds so to calculate the time traveled in half a second we would divide 15/2=7.5
Then we add 30+7.5= 37.5 meters
