The work W done by the electric field in moving the proton is equal to the difference in electric potential energy of the proton between its initial location and its final location, therefore:
where q is the charge of the proton,
, with
being the elementary charge, and
and
are the initial and final voltage.
Substituting, we get (in electronvolts):
and in Joule:
S = ut + 0.5at^2
<span>10 = 0 + 0.5(9.81)t^2 {and if g = 10 then t^2 = 2 so t ~1.414} </span>
<span>t^2 ~ 2.04 </span>
<span>t ~ 1.43 seconds</span>
Pounds
If you are talking about the unit of measurement for weight is that of force it would be Newtons.
Answer:
A. Workdone by helium, W = -1.829KJ
B. Internal energy, DE = 25.271KJ
Explanation:
Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,
W = -P*DV
Where P is the pressure in pascal
DV is the change in volume in m3
DV = Vfinal - Vinitial
= 23.70 - 5.30
= 18.4L
W = -(0.981 * 18.4)
= -18.0504L.atm
Converting L.atm to joule,
= -18.0504 * 101.325
= -1828.97J
= -1.829KJ
If the system loses heat, Q the rection occurring is Exothermic.
Heat is the transfer of energy from one system to another.
Q = mcDT
Where m is the mass of the system
C is the specific heat capacity
Q = 27.20KJ
Internal energy is the summation of the heat supplied to a system and the workdone by the system
DE = Q + W
DE = 27.10 + (-1.829)
= 25.27KJ
