Answer:
False
Explanation:
From the fact that light is emitted in portion, it does not follow that light ray is discrete in structure.
The way Einstein put it was that if a beer is always sold in pint bottles, that does not mean that beer contain of indivisible pint bottles. Yet experiments in which light knocked electrons out of materials insistently made the point that light is absorbed only in the form of discrete portions. An emitted portion or quantum of light energy retains it's individuality in subsequent events as well.
This concept was first stated by Einstein in 1905. From the heuristic point of view that he developed light is always made up of discrete portions possessing energy and momentum.
Answer:
The net force acting on the otter along the incline is 13.96 N.
Explanation:
It is given that,
Mass of the otter, m = 2 kg
Distance covered by otter, d = 85 cm = 0.85 m
It takes 0.5 seconds.
We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :
Here, u = 0 (at rest)
The net force acting on the otter along the incline is given by :
F = ma
F = 13.6 N
So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.
Ohm's law defines the relationship between the voltage, current, and resistance in an electric circuit: i = v/r. The current is directly proportional to the voltage and inversely proportional to the resistance.
Answer:
Fm = 51N and Fj = 26N
Summing the moments about the shoulder joint
Sum of anticlockwise moments = sum of clockwise moments
Fm x 12 = mg x 24
Fm = 2.6 x 9.8 × 24/12
Fm = 51N
Summing the forces acting on the arm
Sum of upward forces = sum of downward forces
Fm = Fj + mg
51 = Fj + 2.6 × 9.8
51 = Fj + 25.48
Fj = 51 - 25.48
Fj = 26N
Explanation:
Newtons first law and the principle of moments have been applied in solving this problem.
Answer:
Explanation:
a) Linear Speed ; v = 590 x 2π/60 x 3.3 = 203.91 m/s
b) We get the radial acceleration of the tip of the blade as
a = w²r or v²/r
a = (203.91 m/s)² / 3.3
= 12600.50 m/s²
Acceleration due to gravity of the earth = 9.8m/s²
ratio of radial acceleration to g = a-rad/g
= 12600.50/ 9.8 = 1285.76g