2 years ago

How does the stratosphere protect us?

Physics

1 answer:

Rudik [331]2 years ago

4 0

<span>It acts as a sunscreen to </span>protect us<span> against UV radiation. </span>

You might be interested in

(Please help asap)

siniylev [52]

The answer would be B

5 0

3 years ago

Which celestial body would have the strongest gravitational pull on a satellite orbiting 100 km above its surface?

8090 [49]

According to the Law of Universal Gravitation, the gravitational force is directly proportional to the mass, and inversely proportional to the distance. In this problem, let's assume the celestial bodies to be restricted to the planets and the Sun. Since the distance is specified, the other factor would be the mass. Among all the celestial bodies, the Sun is the most massive. So, the Sun would cause the strongest gravitational pull to the satellite.

3 0

3 years ago

Read 2 more answers

A step-down transformer providing electricity for a residential neighbor-hood has exactly 2680 turns in its primary. when the po

Fynjy0 [20]

The turns ratio is equal to the voltage ratio. Let n1 and n2 be the primary and secondary turns. Then
5850V/120V=n1/n2
48.75=2680/n2
n2=2680/48.75
n2=55

6 0

3 years ago

Lighting a match results in light and heat. Since energy was not created by the match, what transformation took place?

Yuki888 [10]

Chemical energy stored in the compounds caked on the head of the match, and later the
chemical energy stored in the wood, was released in the form of heat and light when the
chemical compounds got hot enough.

3 0

2 years ago

It decomposes in a first-order reaction with a rate constant of 14 s–1. how long would it take for an initial concentration of 0

VikaD [51]

The rate constant of a reaction can be computed by the ratio of the changes in the concentration and time take taken for it to decompose. Thus, if the rate constant is given to be 14 M/s, we have

$rate = \frac{-(C_{new} - C_{old})}{t}$

where C are the concentration values and t is the time taken for it to decompose.

$14 = \frac{-(0.02 - 0.06)}{t}$
$t = 0.003 s$

Thus, it will take 0.003 s for it to decompose.
Answer: 0.003 s

4 0

3 years ago