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2 years ago

14

I’ll give brainliest!! please help and answer correctly! plsss answer quick

1 answer:

Rashid [163]2 years ago

6 0

Answer: The motion of the object will remain the same

Explanation:

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A child throws a ball with an initial speed of 8.00 m/s at an angle of 40.0° above the horizontal. The ball leaves her hand 1.00

vivado [14]

Answer:

7.5 m

Explanation:

$v$ = initial speed of the ball = 8 m/s

$\theta$ = angle of launch = 40° deg

Consider the motion along the vertical direction :

$v_{oy}$ = initial velocity along vertical direction = $v Sin\theta$ = 8 Sin40 = 5.14 m/s

$a_{y}$ = acceleration along vertical direction = - 9.8 m/s²

$t$ = time of travel

$y$ = vertical displacement = - 1 m

Using the kinematics equation

$y = v_{oy}t + (0.5)a_{y}t^{2}$

$- 1 = (5.14)t + (0.5)(- 9.8)t^{2$

$t$ = 1.22 sec

Consider the motion along the horizontal direction :

$v_{ox}$ = initial velocity along horizontal direction = $v Sin\theta$ = 8 Cos40 = 6.13 m/s

$a_{x}$ = acceleration along vertical direction = 0 m/s²

$t$ = time of travel = 1.22 sec

$x$ = horizontal displacement = ?

Using the kinematics equation

$x = v_{ox}t + (0.5)a_{x}t^{2}$

$x = (6.13)(1.22) + (0.5)(0)(1.22)^{2$

$x$ = 7.5 m

4 0

2 years ago

Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a

timama [110]

Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack ( $v$ ), measured in meters per second, is equal to the product of the angular speed of the wheel ( $\omega$ ), measured in radians per second, and the distance of the tack respect to the rotation axis ( $R$ ), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

$\omega = 2.83\,\frac{rev}{s} \times \frac{2\pi\,rad}{1\,rev}$

$\omega \approx 17.781\,\frac{rad}{s}$

Then, the tangential speed of the tack is: ( $\omega \approx 17.781\,\frac{rad}{s}$ , $R = 0.393\,m$ )

$v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)$

$v = 6.988\,\frac{m}{s}$

The tangential speed of the tack is 6.988 meters per second.

7 0

2 years ago

Think of a famous person and gather information about him/her

dybincka [34]

Abraham Lincoln

Explanation:

hope it helps you a little

4 0

2 years ago

2in+3in+4in+4in+6in+7in calculate the area and perimeter of each shape

ololo11 [35]

Perimeter=26in

Area would be to multiply the units together

4 0

2 years ago

Read 2 more answers

given the question on measuring gravitational acceleration with a pendulum and given results how do I calculate the questions?

balu736 [363]

Answer:

Hindi ko po alam

Explanation:

Kaya sa iba ka nalang mag tanong kac Bobo ako jaan

4 0

2 years ago