Answer:
The final velocity of the runner at the end of the given time is 2.7 m/s.
Explanation:
Given;
initial velocity of the runner, u = 1.1 m/s
constant acceleration, a = 0.8 m/s²
time of motion, t = 2.0 s
The velocity of the runner at the end of the given time is calculate as;

where;
v is the final velocity of the runner at the end of the given time;
v = 1.1 + (0.8)(2)
v = 2.7 m/s
Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.
Answer:
265 J
Explanation:
where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.
Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

acceleration of the car = 0.33 m/s²
Explanation:
To calculate the acceleration of the car we use the following formula:
acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
change in velocity = 23 m/s - 13 m/s = 10 m/s
change in velocity = 10 m/s
acceleration = 10 m/s / 30 s
acceleration = 0.33 m/s²
Learn more about:
acceleration
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The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
- <em>Speed of the driver observed by the stationary police officer, Vo = 44.7 m/s</em>
- <em>Speed of the driver, V = 26.8 m/s.</em>
- <em>Speed limit = 60 mph</em>
The speed limit of the driver in meter per second is calculated as follows;

From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
Learn more about relative velocity here: brainly.com/question/17228388
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