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4 years ago

How to write a linear equation for this problem

Mathematics

1 answer:

Minchanka [31]4 years ago

6 0

I just found out my answer was 40.3 idk if that it just check it

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What is the solution set of this inequality?

Gnoma [55]

Answer:

$x\ge \:4$

Step-by-step explanation:

$8(x-5) -3x\geq -20\\\\\mathrm{Expand\:}8\left(x-5\right)-3x:\quad 5x-40\\\\5x-40\ge \:-20\\\\\mathrm{Add\:}40\mathrm{\:to\:both\:sides}\\\\5x-40+40\ge \:-20+40\\\\Simplify\\\\5x\ge \:20\\\\\mathrm{Divide\:both\:sides\:by\:}5\\\\\frac{5x}{5}\ge \frac{20}{5}\\\\Simplify\\\\x\ge \:4$

8 0

3 years ago

Represent √11.9 on the number line

ikadub [295]

The square root would be 3.4 if rounded to the tenths place

6 0

3 years ago

Find the volume of the sphere with a radius, r, of 3/2 feet and π ≈ 3.14.

nalin [4]

Answer:

V= 14.13

Step-by-step explanation:

Information needed:

V= 4/3 $\pi$ r^3

$\pi$ = 3.14

r= 3/2

Solve:

V= 4/3 $\pi$ r^3

V= 4/3(3.14)(3/2)^3

V= 4/3(3.14)(27/8)

V= 14.13

3 0

3 years ago

Read 2 more answers

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$

4 0

4 years ago

Which choice correctly shows the solution(s) of the equation x2 = 400?

Arada [10]

x2=400

x=√400

=20

20^2=400

5 0

3 years ago