A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
The answer would be 6 I think
LHS=18-3(2p+4)
=18-6p-12
=6-6p
=3(2-2P) hence it is not equal to 3(2-3p)
Answer:
x^2 + 4y^2 + 6x + 4
Step-by-step explanation:
Arranging the terms;
x ^ 2 + y^2 + 3y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 4x + 2x + 2 + 2
x^2 + 4y^2 + 6x + 2 + 2
x^2 + 4y^2 + 6x + 4
Answer:
6m
Step-by-step explanation:
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