Answer:
Empirical formula of 81.8 carbon and 18.2 hydrogen
Steps
- Find the empirical formula of a compound that has 81.8% of Carbon (C), 18.2% of Hydrogen (H).
- Divide by fractional component of each mole value: C=1.5354936431103, H=4.0709872862205Round to closest whole numbers: C=2, H=4
<h3> Combine to get the empirical formula: C2H4</h3>
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The missing element : ₇¹⁴N
<h3>Further explanation</h3>
Given
Reaction
₆¹⁴C ⇒X + ₋₁⁰e
Required
The missing element
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
In a decay reaction, the sum of the mass number and atomic number before and after the decay is the same.
The element X :
Atomic number = 6 + 1 =7
Mass number = 14 + 0 = 14
<u>Answer:</u> The correct answer is Option d.
<u>Explanation:</u>
Electronegativity is defined as the tendency of an element to attract the shared pair of electron towards itself in a compound.
When electron is transferred from less electronegative atom to more electronegative atom.
The atom which is more electronegative gains electron and undergoes reduction reaction.
Reduction reaction is defined as the reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

During the transfer of electrons, energy is released when an electron looses is potential energy during the transfer.
Hence, the correct answer is Option d.
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