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Vikentia [17]
3 years ago
6

How is the environment shown in the picture important to aquatic life zones

Biology
2 answers:
kondor19780726 [428]3 years ago
7 0

here this picture that was missing

i cant help sry

Tanzania [10]3 years ago
3 0
How can we solve it if we don't have the picture?
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How does the structure of DNA explain chargaff's rule?
Flauer [41]

Answer:

Chargaff's rules state that DNA from any species of any organism should have a 1:1 stoichiometric ratio (base pair rule) of pyrimidine and purine bases and, more specifically, that the amount of guanine should be equal to cytosine and the amount of adenine should be equal to thymine

8 0
3 years ago
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A man with type AB blood is married to a woman also with type AB blood. What are the possible
den301095 [7]

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AB

Explanation:

7 0
2 years ago
Enzymes are called catalysts because they
vesna_86 [32]

Answer:True

Explanation:

3 0
3 years ago
1. You are studying the nesting behavior of an unusual species of bird in the Solomon Islands. You discover that baby birds exis
Dafna1 [17]

Answer:

0.78

Explanation:

Fitness measures the probability of survival and reproduction of a particular phenotype or genotype in a population.

Relative fitness measures how fit one genotype or phenotype is with respect to the most fit genotype or phenotype in a popualtion. It is calculated as = survival rate of that group / maximum survival rate observed in that population

Here,

Total number of yellow birds = 263

Yellows birds that survived = 150

Survival rate of yellow birds = 150/263 = 0.57

Total number of grey birds = 413

Grey birds that survived = 303

Survival rate of grey birds = 303/413 = 0.73

Grey birds have more survival rate than yellow birds so their survival rate is maximum in the population.

Fitness of yellow phenotype relative to grey phenotype = survival rate of yellow birds / survival rate of grey birds

= 0.57 / 0.73

= 0.78

Hence, fitness of the yellow phenotype relative to the grey one is 0.78.

5 0
3 years ago
Two humans mate who are heterozygous for earlobe shape where attached earlobes (A) are dominant to free earlobes (a), and earwax
MariettaO [177]

Answer:

3/16

Explanation:

This question involves two different genes coding for earlobe shape and earwax quality. The alleles for attached earlobes (A) and wet earwax (E) are dominant over the alleles for free earlobes (a) and dry earwax (e).

According to this question, two humans mate who are heterozygous for both genes i.e. AaEe × AeEe. Each parent will produce the following gametes: AE, Ae, aE, ae.

Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:

* Attached earlobe, wet earwax (A_E_) = 9/16

* Attached earlobe, dry earwax (A_ee) = 3/16

* Free earlobe, wet earwax (aaE_) = 3/16

* Free earlobe, dry earwax (aaee) = 1/16

Hence, the probability of these parents having their first child with dry earwax (ee) and attached earlobes (A_) i.e. genotype A_ee is 3/16.

7 0
3 years ago
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