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GREYUIT [131]
3 years ago
5

a 1.2 m wire carries a current of 10.0 A in a uniform magnetic field of 0.050T. Find the magnitude of the magnetic force on the

wire.
Physics
1 answer:
rodikova [14]3 years ago
8 0
To calculate we use the formula for a magnetic force in a current-carrying wire expressed as the product of the current, magnetic field and the length of the wire.
 F = I x L x B

where F is the force on the wire, I is the current flowing on the wire, L is the length of the wire and B is the magnetic field.

F = 10.0 A x 1.2 m x 0.050 T
F = 0.60 N
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How do laws differ from theories?
Strike441 [17]

Answer:

A theory is an explanation for what has been shown many times. A scientific law is a relationship in nature that has been proved many times and there are no exceptions.

<h3><u>PLEASE</u><u> MARK</u><u> ME</u><u> BRAINLIEST</u></h3>
6 0
2 years ago
Read 2 more answers
A rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of
choli [55]

Answer:

<em>13.54 tons</em>

Explanation:

Let f be the amount of fuel oxidizer needed

v be the speed

The relationship between them is inverse in nature i.e

f ∝ 1/v

f = k/v

If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v  = 10,000

Substitute and get k

k = fv

k = 3.25 * 10,000

k = 32500

To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s

Recall that f = k/v

f = 32500/2400

f = 13.54 metric tons

<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>

4 0
2 years ago
I need help with questions b and d, that’s all.<br><br> Thank you.
Mkey [24]

b).  The power depends on the RATE at which work is done.  

Power = (Work or Energy) / (time)

So to calculate it, you have to know how much work is done AND how much time that takes.

In part (a), you calculated the amount of work it takes to lift the car from the ground to Point-A.  But the question doesn't tell us anywhere how much time that takes.  So there's NO WAY to calculate the power needed to do it.

The more power is used, the faster the car is lifted.  The less power is used, the slower the car creeps up the first hill.  If the people in the car have a lot of time to sit and wait, the car can be dragged from the ground up to Point-A with a very very very small power ... you could do it with a hamster on a treadmill.  That would just take a long time, but it could be done if the power is small enough.

Without knowing the time, we can't calculate the power.

...

d).  Kinetic energy = (1/2) · (mass) · (speed squared)

On the way up, the car stops when it reaches point-A.  

On the way down, the car leaves point-A from "rest".

WHILE it's at point-A, it has <u><em>no speed</em></u>.  So it has no (<em>zero</em>) kinetic energy.

7 0
2 years ago
A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe
Allushta [10]

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

P = \sigma Ae\Delta T^4

Where

A = Surface area of the Object

\sigma = Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

A = 1.36m^2

\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4

\sigma = 5.67*10^{-8} J/(s m^2 K^4)

P = 122J/s

e = 0.7

Replacing at our equation and solving to find the temperature 1 we have,

P = \sigma Ae\Delta T^4

P = \sigma Ae (T_2^4 -T_1^4)

122 = (5.67*10^{-8})(1.36)(0.7)(307^4-T_1^4)

T_1 = 285.272K = 12.122\°C

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

8 0
3 years ago
3. Suppose that a block is pulled 16 meters across a floor. What amount of work is done if the force used to drag the block is 2
Nadusha1986 [10]

Explanation:

Work is the product of force and distance.

W = F×d

W = (22 N) × (16 m)

W = 352 J

7 0
3 years ago
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