Question

The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thus CO2 diffuses_______ C3H8.
Slower Than
Faster Than
The Same As

Answer 1

Answer:  $CO_2$ gas diffuses faster than $C_3H_8$

Explanation:

Diffusion of a gas is defined as the amount of volume of gas displaced in a given amount of time. The diffusion of gas is determined by using Graham's Law.

This law states that the rate of diffusion of gas is inversely proportional to the square root of its molar mass. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

More the molar mass of the gas, its rate of effusion will be less and vice-versa.

We are given:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of propane = 44.10 g/mol

As, the molar mass of carbon dioxide is less than the molar mass of propane by 0.1 unit, so rate of diffusion of carbon dioxide is faster than the rate of effusion of propane.

Hence, $CO_2$ gas diffuses faster than $C_3H_8$

Answer 2

The molecular weight of carbon dioxide (CO2) is 44.00 a.m.u., and the molecular weight of propane gas (C3H8) is 44.10 a.m.u. Thus CO2 diffuses_______ C3H8.

Slower Than

Faster Than

The Same As

Slower than