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MatroZZZ [7]
3 years ago
13

Friction is a (1)______

Physics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

friction is motion heat that collect hot vibration

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What is the force of repulsion between two points positive charges 5 and 8 separated at a distance of 0.02m apart
Zinaida [17]

Explanation:

F =(frac{1}{4{pi}{varepsilon}_o}) x (frac {q_1q_2}{r^2})

F =(frac {5 {times} 10 {times} 8 {times} 10}{0.002 {times} 0.002}) x 9 x 10

F = 900N

4 0
2 years ago
Suppose the gravitational force between two spheres is 100 N. If the distance between the spheres is halved, what is the new gra
natima [27]

Answer:

The gravitational force becomes 4 times i.e 400N

Explanation:

8 0
3 years ago
1. What are Earth's natural climate cycles?
NARA [144]
The Earth's natural climate cycle
Over the last 800,000 years, there have been natural cycles in the Earth's climate. There have been ice ages and warmer interglacial periods. After the last ice age 20,000 years ago, average global temperature rose by about 3°C to 8°C, over a period of about 10,000 years.
3 0
3 years ago
A 4.00-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 27.0 N is require
NikAS [45]

Answer:

a)

135Nm⁻¹

b)

0.925 Hz

c)

1.2ms⁻¹

d)

0 m

e)

6.7ms⁻²

f)

\pm 0.2 m

Explanation:

a)

F = force required to hold the object at rest connected with stretched spring = 27 N

x = stretch in the spring from equilibrium position = 0.2 m

k = force constant of the spring

force required to hold the object at rest is same as the spring force , hence

F = k x

k = \frac{F}{x}

inserting the values

k = \frac{27}{0.2} = 135 Nm⁻¹

b)

frequency of the oscillations is given as

f =\frac{1}{2\pi }\sqrt{\frac{k}{m}}

inserting the values

f =\frac{1}{2(3.14) }\sqrt{\frac{135}{4}}\\f = 0.925 Hz

c)

A = Amplitude of oscillations = 0.2 m

w = angular frequency

Angular frequency is given as

w = 2\pi f = 2 (3.14) (0.925) = 5.8 rads⁻¹

Maximum speed of oscillation is given as

v_{max} = Aw

v_{max} = (0.2)(5.8)\\v_{max} = 1.2 ms⁻¹

d)

maximum speed of the object occurs at the equilibrium position, hence

x = 0 m

e)

Maximum acceleration of oscillation is given as

a_{max} = Aw^{2}

a_{max} = (0.2)(5.8)^{2}\\a_{max} = 6.7ms⁻²

f)

maximum acceleration occurs when the object is at extreme positions, hence

x = \pm 0.2 m

4 0
3 years ago
An unpolarized light with an intensity of 20W/m^2 is passed through a pair of polarizers. The first polarizer is set at an angle
bogdanovich [222]

Answer:

4.416 W/m²

Explanation:

Malus' law is given mathematically as

I = I₀ cos² θ

For the first polarizer, θ = 60°

I₁ = I₀ cos² 60°

I₁ = I₀ (0.5)² = 0.25I₀

For the second polarizer, θ = 20°

I₂ = I₁ cos² 20°

I₂ = I₁ (0.9397)² = 0.883 I₁

I₂ = 0.883 × 0.25I₀ = 0.2208 I₀

Note that

I₀ = 20 W/m²

I₂ = 0.2208 × 20 = 4.416 W/m²

Hope this Helps!!!

6 0
3 years ago
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