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Kaylis [27]
3 years ago
10

Dipole-induced dipole attractions exist between molecules of water and molecules of gasoline, yet these two substances do not mi

x because water has such a strong attraction for itself. which compound might best help these two substances mix into a single liquid phase
Chemistry
1 answer:
lana [24]3 years ago
3 0

Gasoline is predominantly octane, C8H18.  Something like soap would be a great homogenizer.  Soap is composed of a long hydrocarbon chain with a tiny, highly polar tip on one end.  Usually, the soap is the anion of a salt, NaX.  This allows the polar end of the soap to stick to water, while the nonpolar end sticks to the oil.

\frac{kg*m*m}{m^3*s*\mu}=1=\frac{kg}{m*s*\mu}

\mu=\frac{kg}{m*s}

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What is a displacement reactions​
Alisiya [41]

<h2><u>Question</u><u>:</u>-</h2>

\textsf{what is a displacement reactions?   }      

<h2><u>Answer</u><u>:</u></h2>

\large \underbrace{ \underline{ \sf Displacement \: reaction}}

The reaction in which more reactive element replace a less reactive element from its compound is called displacement reaction.

Ex:-

\bold{\large Zn+HCl \longrightarrow ZnCl_2+H_2}

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_______ in the mountains melts into water.<br>​
Zigmanuir [339]

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A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
4 years ago
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