Answer:
if i consider this reaction
Fe2O3+ 3CO---》2Fe+ 3CO2
so let's calculate first moles of Fe2O3 i.e. = 256/159.69= 1.6 moles
So the one moles of Fe2O3 is forming three moles of CO2
hence 1.6 moles will form 4.8 moles of CO2
one mole of CO2 is 44 g so 4.8 moles of Co2 is 44×4.8= 211.2 g
so the conclusion is 211.2 g of CO2 can be produced from 256 g Fe2O3!!
i d k it's right or wrong but i tried my best :)
Answer:
The volume is 583.02 mL
Explanation:
Given that the density is:-
The mass,
The expression for the calculation of density is shown below as:-
Using the above expression to calculate the volume as:-
Applying the values to calculate the volume as:-
<u>The volume is 583.02 mL.</u>
Answer:
A). An atom is an indivisible hard-sphere.
Explanation:
The 'Atomic Theory' of Dalton is characterized as the earliest model(came in 1803) which described the atoms as the indivisible and resistant spheres. He <u>used the example of watermelon to elaborate that the atoms of a specific element share similar characteristics</u> and the atoms of distinct elements differ in their mass as well as their size. Thus, <u>option A</u> is the correct answer.
Answer: The percent yield for the
is, 86.7 %
Explanation : Given,
Moles of
= 2.36 mol
Moles of
= 6.14 mol
First we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 2 moles of
react to give 6 moles of
So, 2.36 moles of
react to give
mole of
Now we have to calculate the percent yield for the
.
Experimental yield = 6.14 moles
Theoretical yield = 7.08 moles
Now put all the given values in this formula, we get:
Therefore, the percent yield for the
is, 86.7 %
Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:

Putting values in above equation, we get:

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
solution to the endpoint