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Kaylis [27]
3 years ago
10

Dipole-induced dipole attractions exist between molecules of water and molecules of gasoline, yet these two substances do not mi

x because water has such a strong attraction for itself. which compound might best help these two substances mix into a single liquid phase
Chemistry
1 answer:
lana [24]3 years ago
3 0

Gasoline is predominantly octane, C8H18.  Something like soap would be a great homogenizer.  Soap is composed of a long hydrocarbon chain with a tiny, highly polar tip on one end.  Usually, the soap is the anion of a salt, NaX.  This allows the polar end of the soap to stick to water, while the nonpolar end sticks to the oil.

\frac{kg*m*m}{m^3*s*\mu}=1=\frac{kg}{m*s*\mu}

\mu=\frac{kg}{m*s}

You might be interested in
How many g of CO2 can be produced from 256 g Fe2O3?
kotykmax [81]

Answer:

if i consider this reaction

Fe2O3+ 3CO---》2Fe+ 3CO2

so let's calculate first moles of Fe2O3 i.e. = 256/159.69= 1.6 moles

So the one moles of Fe2O3 is forming three moles of CO2

hence 1.6 moles will form 4.8 moles of CO2

one mole of CO2 is 44 g so 4.8 moles of Co2 is 44×4.8= 211.2 g

so the conclusion is 211.2 g of CO2 can be produced from 256 g Fe2O3!!

i d k it's right or wrong but i tried my best :)

7 0
2 years ago
The density of ethanol is 0.789 g/mL. If you need 460.0 g of ethanol for an experiment, how many milliliters would you measure o
4vir4ik [10]

Answer:

The volume is 583.02 mL

Explanation:

Given that the density is:-

\rho=0.789\ g/mL

The mass, m=460.0\ g

The expression for the calculation of density is shown below as:-

\rho=\frac{m}{V}

Using the above expression to calculate the volume as:-

V=\frac{m}{\rho}

Applying the values to calculate the volume as:-

V=\frac{460.0\ g}{0.789\ g/mL}=583.02\ mL

<u>The volume is 583.02 mL.</u>

3 0
3 years ago
1. Which statement describes the earliest model of<br><br> the atom?
zloy xaker [14]

Answer:

A). An atom is an indivisible hard-sphere.

Explanation:

The 'Atomic Theory' of Dalton is characterized as the earliest model(came in 1803) which described the atoms as the indivisible and resistant spheres. He <u>used the example of watermelon to elaborate that the atoms of a specific element share similar characteristics</u> and the atoms of distinct elements differ in their mass as well as their size. Thus, <u>option A</u> is the correct answer.

5 0
3 years ago
Ill give the brainliest answer to whoever helps me with this equation
vampirchik [111]

Answer: The percent yield for the NaBr is, 86.7 %

Explanation : Given,

Moles of FeBr_3 = 2.36 mol

Moles of NaBr = 6.14 mol

First we have to calculate the moles of NaBr

The balanced chemical equation is:

2FeBr_3+3Na_2S\rightarrow Fe_2S_3+6NaBr

From the reaction, we conclude that

As, 2 moles of FeBr_3 react to give 6 moles of NaBr

So, 2.36 moles of FeBr_3 react to give \frac{6}{2}\times 2.36=7.08 mole of NaBr

Now we have to calculate the percent yield for the NaBr.

\text{Percent yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

Experimental yield = 6.14 moles

Theoretical yield = 7.08 moles

Now put all the given values in this formula, we get:

\text{Percent yield}=\frac{6.14mol}{7.08mol}\times 100=86.7\%

Therefore, the percent yield for the NaBr is, 86.7 %

6 0
3 years ago
How much of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH
Ivan

Answer: 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HNO_3

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=1\\M_1=0.5M\\V_1=?mL\\n_2=1\\M_2=0.05M\\V_2=25.0mL

Putting values in above equation, we get:

1\times 0.5\times V_1=1\times 0.05\times 25.0\\\\V_1=2.5mL

Thus 2.5 ml of 0.5 M HNO3 is necessary to titrate 25.0 mL of 0.05 M KOH

solution to the endpoint

6 0
3 years ago
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