1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liubo4ka [24]
3 years ago
9

Whya re resources in north korea limited

Engineering
1 answer:
Delvig [45]3 years ago
3 0

Answer:

because then people can get knowledge about the outside world and how modern they are unlike the country

Explanation:

You might be interested in
Consider the following hypothetical scenario for Jordan Lake, NC. In a given year, the average watershed inflow to the lake is 9
dybincka [34]

Answer:

The lake can withdraw a maximum of 1.464\times 10^{10} cubic feet per year to provide water supply for the Triangle area.

Explanation:

The maximum amount of water that can be withdrawn from the lake is represented by the following formula:

V = V_{in}+V_{p}-V_{e}-V_{out} (Eq. 1)

Where:

V - Available amount of water for water supply in the Triangle area, measured in cubic feet per year.

V_{in} - Inflow amount of water, measured in cubic feet per year.

V_{out} - Amount of water released for the benefit of fish and downstream water users, measured in cubic feet per year.

V_{p} - Amount of water due to precipitation, measured in cubic feet per year.

V_{e} - Amount of evaporated water, measured in cubic feet per year.

Then, we can expand this expression as follows:

V = f_{in}\cdot \Delta t+h_{p}\cdot A_{l}-h_{e}\cdot A_{l}-f_{out}\cdot \Delta t

V = (f_{in}-f_{out})\cdot \Delta t +(h_{p}-h_{e})\cdot A_{l} (Eq. 2)

Where:

f_{in} - Average watershed inflow, measured in cubic feet per second.

f_{out} - Average flow to be released, measured in cubic feet per second.

\Delta t - Yearly time, measured in seconds per year.

h_{p} - Change in lake height due to precipitation, measured in feet per year.

h_{e} - Change in lake height due to evaporation, measured in feet per year.

A_{l} - Surface area of the lake, measured in square feet.

If we know that f_{in} = 900\,\frac{ft^{3}}{s}, f_{out} = 300\,\frac{ft^{3}}{s}, \Delta t = 31,536,000\,\frac{second}{yr}, h_{p} = 32\,\frac{in}{yr}, h_{e} = 55\,\frac{in}{yr} and A_{l} = 47,000\,acres, the available amount of water for supply purposes in the Triangle area is:

V = \left(900\,\frac{ft^{2}}{s}-300\,\frac{ft^{3}}{s} \right)\cdot \left(31,536,000\,\frac{s}{yr} \right) +\left(32\,\frac{in}{yr}-55\,\frac{in}{yr} \right)\cdot \left(\frac{1}{12}\,\frac{ft}{in}\right)\cdot (47000\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)V = 1.464\times 10^{10}\,\frac{ft^{3}}{yr}

The lake can withdraw a maximum of 1.464\times 10^{10} cubic feet per year to provide water supply for the Triangle area.

5 0
3 years ago
An insulated 40 ft3 rigid tank contains air at 50 lbf/in2 and 120oF. A valve connected to the tank is now opened, and air is all
goldfiish [28.3K]

Answer:

The electrical work for the process is 256.54 Btu.

Explanation:

From the ideal gas equation:

n = PV/RT

n is the number of moles of air in the tank

P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2

V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3

T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K

R is gas constant = 8.314 J/mol.k

n = 344736.2×1.133/8.314×321.9 = 145.94 mol

The thermodynamic process is an isothermal process because the temperature is kept constant.

W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu

5 0
3 years ago
Read 2 more answers
A classroom which normally contains 26 people is to be air- conditioned. A person in the classroom typically dissipates heat at
lutik1710 [3]

Answer:

Explanation:

Heat dissipated by 26 people per second

= 26 x 360 x 1000 / (60 x 60)

= 2600 J

Heat dissipated by bulbs per second

= 15 x 40

= 600 J

Heat dissipated by fans per second

200 J

Heat dissipated by air coming in

= 200 x 10 x 1000 / (60 x 60)

=555.55 J

Heat gain by walls

= 5000 x 1000 / (60 x 60)

= 1388.88 J

Total heat gain per second

= 2600 + 600+200+555.55

= 3955.55 J

Capacity of air-conditioner required

= 3955.55 J/s

= 3.9 kJ/s

= 3.9kW

= 4 kW

7 0
3 years ago
What are some of the trade-offs of a move to an enterprise-level analytics solution for individual end users who might have grow
aleksandrvk [35]

Answer:

THE thing is 435

Explanation:

3 0
3 years ago
Como se usa ffmpeg ayuda porfaaaaa
jonny [76]
Oop
——————————————————————
6 0
3 years ago
Read 2 more answers
Other questions:
  • Suppose we include the lead resistance in the calculation of temperature for a class A RTD. If R3 = 1000 ohms, Ra = 18 ohms, V0
    12·1 answer
  • A strain gauge with a 4 mm gauge length gives a displacement reading of 1.5 um. Calculate the stress at the location of the stra
    5·1 answer
  • A multistage pump is required to deliver water to a head of 50 m at flow rate of 0.1 m^3/s. A motor rotating at 1800 rpm is avai
    8·1 answer
  • A 4140 steel shaft, heat-treated to a minimum yield strength of 100 ksi, has a diameter of 1 7/16 in. The shaft rotates at 600 r
    13·2 answers
  • You're about to make a measurement with an oscilloscope when you find that the trace appears to be very weak on the screen. Whic
    15·2 answers
  • A solid square rod is cantilevered at one end. The rod is 1 m long and supports a completely reversing transverse load at the ot
    5·1 answer
  • 1. Asphyxiation is a hazard posed by Compressed Natural Gas (CNG) vehicles and can be detected when you notice
    7·1 answer
  • Pls help me with these 3 ez questions.
    8·2 answers
  • A straight pull contains two raceways. One of the raceways has a trade size of 3
    5·1 answer
  • If a resistor only has three color bands, it has a tolerance of 20 percent. What would this mean for a resistor specified at 10,
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!