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3 years ago

How much horse power does a Lamborghini have

Engineering

2 answers:

4vir4ik [10]3 years ago

5 0

Answer:

Countach - 375
Huracan - 610 to 630
Aventador - 729 to 759
Urus - 641
Gallardo - 543 to 562
Centenario - 770
SCV12 - 830

Explanation:

It really all depends, it varies from 375 to 830, you can't mark one as " Lamborghinis have this much hp always " seeing it fluctuates so much car to car

statuscvo [17]3 years ago

4 0

The Lamborghini SCV12 has 830 horse power.

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3 years ago

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Answer:

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3 years ago

Dampness or moisture introduces ____ into the weld, which causes cracking when some metals are welded.

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2 years ago

Very thin films are usually deposited under vacuum conditions to prevent contamination and ensure that atoms can fly directly fr

katrin [286]

Answer:

a. 9947 m

b. 99476 times

c. 2*10^11 molecules

Explanation:

a) To find the mean free path of the air molecules you use the following formula:

$\lambda=\frac{RT}{\sqrt{2}\pi d^2N_AP}$

R: ideal gas constant = 8.3144 Pam^3/mol K

P: pressure = 1.5*10^{-6} Pa

T: temperature = 300K

N_A: Avogadros' constant = 2.022*10^{23}molecules/mol

d: diameter of the particle = 0.25nm=0.25*10^-9m

By replacing all these values you obtain:

$\lambda=\frac{(8.3144 Pa m^3/mol K)(300K)}{\sqrt{2}\pi (0.25*10^{-9}m)^2(6.02*10^{23})(1.5*10^{-6}Pa)}=9947.62m$

b) If we assume that the molecule, at the average, is at the center of the chamber, the times the molecule will collide is:

$n_{collision}=\frac{9947.62m}{0.05m}\approx198952\ times$

c) By using the equation of the ideal gases you obtain:

$PV=NRT\\\\N=\frac{PV}{RT}=\frac{(1.5*10^{-6}Pa)(\frac{4}{3}\pi(0.05m)^3)}{(8.3144Pa\ m^3/mol\ K)(300K)}=3.14*10^{-13}mol\\\\n=(3.14*10^{-13})(6.02*10^{23})\ molecules\approx2*10^{11}\ molecules$

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3 years ago

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GREYUIT [131]

Answer:

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Explanation:

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3 years ago