Answer:
Explanation:
From the question we are told that:
Water flow Rate
Initial Temperature
Final Temperature
Let
Specific heat of water
And
Generally the equation for Heat transfer rate of water is mathematically given by
Heat transfer rate to water= mass flow rate* specific heat* change in temperature
Therefore
Answer:
c
Explanation:
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Answer:
endurance length is 236.64 MPa
Explanation:
data given:
d = 37.5 mm
Sut = 760MPa
endurance limit is
Se = 0.5 Sut
= 0.5*760 = 380 MPa
surface factor is
Ka = a*Sut^b
where
Sut is ultimate strength
for AISI 1040 STEEL
a = 4.51, b = -0.265
Ka = 4.51*380^{-0.265}
Ka = 0.93
size factor is given as
Kb =1.29 d^{-0.17}
Kb = 0.669
Se = Sut *Ka*Kb
= 380*0.669*0.93
Se = 236.64 MPa
therefore endurance length is 236.64 MPa
Answer:
A. S0 = 1, S1 = 0, S2 = 0
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Answer:
The strength coefficient is and the strain-hardening exponent is
Explanation:
Given the true strain is 0.12 at 250 MPa stress.
Also, at 350 MPa the strain is 0.26.
We need to find and the .
We will plug the values in the formula.
We will solve these equation.
plug this value in
Taking a natural log both sides we get.
Now, we will find value of
So, the strength coefficient is and the strain-hardening exponent is .