A river flows due east at 12 km/h. A boat crosses the 720 m wide river by maintaining a constant velocity of 72 mi/h due north r
elative to the water. If no correction is made for the current, how far downstream does the boat move by the time it reaches the far shore?
1 answer:
Answer:
The boat will be 74 .17 meters downstream by the time it reaches the shore.
Explanation:
Consider the vector diagrams for velocity and distance shown below.
converting 72 miles per hour to km/hr
we have 72 miles per hour 72 × 1.60934 = 115.83 km/hr
The velocity vectors form a right angled triangle, and can be solved using simple trigonometric laws
This is the vector angle with which the ship drifts away with respect to its northward direction.
<em>From the sketch of the displacement vectors, we can use trigonometric ratios to determine the distance the boat moves downstream.</em>
Let x be the distance the boat moves downstream.d
∴The boat will be 74 .17 meters downstream by the time it reaches the shore.
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No, it is impossible
Explanation:
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if height is maximum:
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<h3>Analysis: From the last equation we see that the maximum height depends ONLY on the initial speed. This means that if both objects reach the same maximum height, then they necessarily need to have the SAME initial velocity. If they have the same initial velocity and in order to reach the maximum height at the SAME time the only way is that they are released at the SAME TIME.
In a gear train with two gears, the gear ratio is defined as follows
where
is the angular velocity of the input gear while 
is the angular velocity of the output gear.
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The acceleration of the particle at time t is:
The velocity of the particle at time t is given by the integral of the acceleration a(t):
and the position of the particle at time t is given by the integral of the velocity v(t):
Assuming the particle starts from position x(0)=0 at t=0, the distance the particle covers in the first t=2 seconds can be found by substituting t=2 s in the equation of x(t):
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and the position of the particle at time t is given by the integral of the velocity v(t):
Assuming the particle starts from position x(0)=0 at t=0, the distance the particle covers in the first t=2 seconds can be found by substituting t=2 s in the equation of x(t):