The answer is 
. A magnesium atom has 12 protons and an arrangement of [2, 8, 2]. When you lose two electrons, arrangement becomes [2,8] and the atom becomes a positively charged ion
Answer:
different reactants
Explanation:
because if you think about it what's really thick and it takes a lot longer to burn a piece of paper is super fit material which can just tear real easily just by ripping it with your fingers so if you think about it how fast it burns it's not how big the molecules are because paper has smaller molecules than wood would so the paper burns faster in differently so it's probably the reactant it's made of
Answer:
Mass of Analyte H2C2O4 = 18.18 grams
Explanation:
The balanced equation is:
The Molarity of Oxalic acid needed can be determined using:
Here M1 = Molarity of Oxalic acid
V1 = Volume of oxalic acid
M2 = Molarity of KOH and V2 = Volume of KOH
M1 = ? , V1 = 16.8 mL , M2 = 0.501 M , V2 = 13.54 mL
Put the values and solve for M2,
We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH
Hence Molarity of H2C2O4 =
0.202 M
Molar mass = H2C2O4 = 2x1 +2x12 + 4x16
= 2+24+64 = 90 gram
18.18 gram
Answer:
1.67 gradius Celcius
Explanation:
Please see the step-by-step solution in the picture attached below.
Hope this answer can help you. Have a nice day!
Answer:
6.25 g
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Original amount (N₀) = 200 g
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Number of half-lives (n) =
n = t / t½
n = 344 / 68.8
n = 5
Thus, 5 half-lives has elapsed.
Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:
Original amount (N₀) = 200 g
Number of half-lives (n) = 5
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2⁵ × 200
N = 1/32 × 200
N = 200 / 32
N = 6.25 g
Thus, the amount of Uranium-232 that remains is 6.25 g
