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2 years ago

An ideal ammeter would have zero resistance while an ideal voltmeter would have infinite resistance, why?.

1 answer:

6 0

Answer: An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.

Explanation: To find the answer, we need to know about the Ammeter and Voltmeter.

<h3>What is an ammeter?</h3>

An ammeter is a device, that can be used to measure the electric current flows through a circuit in amperes.

An ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance when it is connected in series to measure the current.

<h3>What is voltmeter?</h3>

A voltmeter is a device, that can be used to measure the electric potential difference generated between the terminals of an electric circuit in volts.

An ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter, when it is connected in parallel to measure the voltage.

Thus, we can conclude that, an ideal ammeter would have zero resistance, because to ensure that, there is no voltage drop due to the internal resistance. Similarly, an ideal voltmeter would have infinite resistance, because to ensure that there is no current is drawn by the voltmeter.

Learn more about the ammeter and voltmeter here:

brainly.com/question/28044897

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A stick of mass m and length / is pivoted at one

AfilCa [17]

Answer:

Potential Energy = mgl (1 - cosθ)

Explanation:

<h3>Given :-</h3>

Mass of stick = m
Length of stick = l
Angle = θ

Increase potential energy

<h3>Solution :-</h3>

✪ <u>According to the given </u><u>data</u> :-

⠀⠀⠀→ cosθ = ᵇ/ₕ

⠀⠀⠀→ cosθ = ᴬᴮ/l

⠀⠀⠀→ AB = l cosθ

❂ <u>For </u><u>Height</u> :-

⠀⠀⠀→ h = l - l cosθ

⠀⠀⠀→ h = l (1-cosθ)

☯ <u>As we know that</u>

⠀⠀⠀→ Potential Energy = mgh

⠀⠀⠀→ Potential Energy = mg × l (1-cosθ)

⠀⠀⠀→ Potential Energy = mgl (1-cosθ)

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3 years ago

A. Una onda armónica que se propaga por un medio unidimensional tiene una frecuencia de 500Hz y una velocidad de propagación de

Natasha2012 [34]

Answer:

0.117 m

Explanation:

First of all, we can find the wavelength of the wave in the problem, by using the wave equation:

$v=f\lambda$

where:

v = 350 m/s is the speed of the wave

f = 500 Hz is the frequency of the wave

$\lambda$ is the wavelength

Solving for $\lambda$ ,

$\lambda=\frac{v}{f}=\frac{350}{500}=0.7 m$

This means that the distance between two consecutive points of the wave having a difference of phase of

$\phi=2\pi$

is 0.7 m.

Here we want to find the distance between two points that have a difference of phase of

$\phi'=\frac{\pi}{3}$

So, we can set up the following rule of three:

$\frac{d}{\phi}=\frac{d'}{\phi'}$

where d' is the distance we are looking for. Solving for d',

$d'=d\frac{\phi'}{\phi}=(0.7)\frac{\pi/3}{2\pi}=\frac{1}{6}(0.7)=0.117 m$

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3 years ago

True or false. More people live in cities then they do in the country

iVinArrow [24]

Answer:

Explanation:

That's my answer hope it helped

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3 years ago

The velocity of a 640-kg auto is changed from 10.0 m/s to 44.0 m/s in 71.0 s by an external, constant force. (a) What is the res

n200080 [17]

Answer:

(a) <em>change in momentum of the car = 21760 kgm/s</em>

(b) <em>The magnitude of the force = 306.48 N</em>

Explanation:

<em>(a)</em>

<em>Change in momentum: </em><em>This is the product of mass and change in velocity. The unit of momentum is kgm/s. It can be expressed mathematically as,</em>

Change in momentum of the car = m(v-u)................. Equation 1

Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car.

<em>Given: m = 640 kg, v = 44.0 m/s, u = 10.0 m/s.</em>

<em>Substituting these values into equation 1,</em>

<em>Change in momentum of the car = 640 (44-10)</em>

<em>change in momentum of the car = 640× 34</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>change in momentum of the car = 21760 kgm/s</em>

<em>(b) Force:</em><em> Force of a body can be defined as the product of mass and its acceleration. It is measured in Newton (N). It can be expressed mathematically as,</em>

<em>Force = ma ................................ Equation 2</em>

<em> </em><em> Or</em>

<em>Force = m(v-u)/t...................................... Equation 3</em>

<em>Where m = mass of the car, v = final velocity of the car, u = initial velocity of the car, a = acceleration of the car, t = time taken to change the velocity.</em>

<em>Given: m = 640 kg, u = 10.0 m/s v = 44 m/s, t = 71 s.</em>

<em>Substituting these values into equation 3</em>

<em>Force = 640(44-10)/71</em>

<em>Force = (640×34)/71</em>

<em>Force = 306.48 N</em>

<em>The magnitude of the force = 306.48 N</em>

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