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NISA [10]
3 years ago
14

An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. Wh

at is its mass?
Physics
1 answer:
Softa [21]3 years ago
5 0

Answer:

m = 2218.67 kg

Explanation:

It is given that,

Initial velocity, u = 7.5 m/s

Final speed of an object, v = 0 (at rest)

Force, F = 5.2 kN

Time, t = 3.2 s

We need to find the mass of the object. Force acting on an object is given by :

F = ma

m is mass, a is acceleration

F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg

So, the mass of the object is 2218.67 kg

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Un bloque de 2.5kg de masa es empujado 2.2m a lo largo de una mesa horizontal sin fricción por una fuerza constante de 16.0 N di
Tanzania [10]

Answer:

Explanation:

(a) The applied force has two components Fx and Fy. The Fx component is the only one that does work

W_{x}=F_{x}x=(16N)cos(25)(2.2m)=31.9J

(b) There in no net force in the vertical component

F_{N}-F_{y}-F_{g}=0\\F_{N}=F_{y}+F_{g}=(16N)sin(25)+(2.5kg)(9.8\frac{m}{s^{2}})=31.26N

(c)

F_{g}=Mg=(2.5kg)(9.8\frac{m}{s^{2}})=24.5N

(d)

F_{T}=F_{x}=(16N)cos(25)=14.5N

I attached an scheme of the force diagram

8 0
3 years ago
After a water had boiled, the temperature of the water decreases by 22degrees. The mass of the water in the kettle is 0.50kg.The
kifflom [539]

<u>Answer</u>

46,200 J

The energy of given out when a substance is losing heat is given by:

H = mcΔθ

Where m is the mass of the substance,

            c is the specific heat capacity of the substance and

           Δθ is the temperature change.

H = 0.50 × 22 4200

  = 46,200 Joules.

4 0
3 years ago
____________ showed that matter and energy are two forms of the same thing.
Darya [45]
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3 years ago
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Which jovian planet should have the most extreme seasonal changes?
saul85 [17]

Answer:

Uranus

Explanation:

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7 0
2 years ago
Let's take two balls, each of radius 0.1 meters and charge them each to 3 microCoulombs. Then, let's put them on a flat surface
salantis [7]

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

                      = 2 \times 0.1 m

                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = \frac{k \times Q \times Q}{R}

                    = \frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}

                    = 0.081 J

As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, \frac{U}{2}.

Hence,   K.E = \frac{U}{2}

                     = \frac{0.081}{2}

                     = 0.0405 J

Now, we will calculate the speed of balls as follows.

                 V = \sqrt{\sqrt{\frac{2 \times K.E}{m}}

                     = \sqrt{\sqrt{\frac{2 \times 0.0405}{4 kg}}

                     = 0.142 m/s

Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

6 0
2 years ago
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